t1spng03sol - PHYSICS 2306 TEST #1 14 February 2003 2:30 PM...

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PHYSICS 2306 TEST #1 14 February 2003 – 2:30 PM in McBryde 113 Lecture Section 8:00 – 8:50 M,W 3”x5” Note Card and Calculator Allowed 90 Minutes Allowed SOLUTIONS _________________________ ____________________ ________________________ (Name - Printed) (Student I.D.) (Signed Pledge - See Below) I pledge that the answers submitted by me represent only my work. Further, I pledge to refrain from communicating any information about this test to anyone until after the results of this test are returned. Please fill in the three entries specified above. Please record your answers to problems #1 through #20 on the op-scan answer sheet. Please remember to darken on the op-scan sheet the entries corresponding to your student I.D. Do not put your name on the op-scan sheet unless you do not mind your I.D. and name being associated with each other. Please return the question sheets in a stapled packet to the appropriate stack on the front table; and return the op-scan answer sheet to the other appropriate stack on the front table. No credit will be given if any question or answer sheets are missing from your exam. Constants and Conversion Factors: charge of electron(magnitude) or proton: e = 1 . 6 x 10 - 19 C Coulomb’s law constant: k e = 1/4 πε o = 8.99 x 10 9 (N m 2 /C 2 ) Permittivity of free space: ε o = 8 . 854 x 10 - 12 (C 2 /N m 2 ) Use as the speed of sound in air: v = 340 m/s Minimum detectable sound intensity I o = 10 -12 (W/m 2 ) For ε << 1 and ± , and b any ± number (1 + ε ) b 1 + b ⋅ε + (1/2) [b (b-1)] ε 2 + … sin α + sin β = 2 sin[( α + β )/2] cos[( α β )/2] cos α + cos β = 2 cos[( α + β )/2] cos[( α β )/2] sin( α+β ) = sin( α ) cos( β ) + cos( α ) sin( β ) cos( α+β ) = cos( α ) cos( β ) sin( α ) sin( β )
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1. Two sinusoidal transverse traveling waves are moving in opposite directions along the x-axis. They have the same wavelength and frequency, and each has a maximum amplitude of A. The condition on each of the waves is that at x = 0 when t = 0, the disturbance of each is +A. The combined disturbance for both traveling waves at x = 0 when t = T/4, where T is the period of each traveling wave, is: Since each piece of string describes simple harmonic motion, if they are fully up at t = 0, then at T/4 they are both going through equilibrium. Therefore, 0 + 0 = 0. (1) -2A (2) -A (3) 0 (4) +A/2 (5) +A (6) +2A 2. Two identical triangular-shaped wave pulses (isosceles triangles) approach each other from opposite directions. They each have the same speed relative to the ground, and their individual widths are 0 . 4 m each (base of the triangle). After 3 seconds the net disturbance is shown in the bottom picture[see below]. The speed of each pulse is about: Since the two pulses move at the same speed, their peaks will overlap when each has moved 1 meter.
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This note was uploaded on 03/19/2008 for the course PHYS 2306 taught by Professor Ykim during the Fall '06 term at Virginia Tech.

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t1spng03sol - PHYSICS 2306 TEST #1 14 February 2003 2:30 PM...

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