Electric Circuits (6th ed) by Nilsson (Answers Problems)

Electric Circuits (6th ed) by Nilsson (Answers Problems) -...

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APPENDIX G Answers to Selected Problems Chapter 1 1.1 8.85 ms 1.3 38 m/s 1.5 361.934 µ m 2 1.7 0.962 aJ 1.9 6480 J 1.11 a) 400 W, delivering b) Entering c) Gain 1.15 a) 3.1 mW b) 1.24 µ J c) 21.67 µ J 1.18 a) 0.5 W b) 2 mJ 1.21 a) 1.68 ms b) 666 mW c) 2.97 mJ 1.26 1740 W Chapter 2 2.3 yes; 720 W 2.8 2240 W 2.11 a) 4 A b) 144 V c) 768 W 2.16 a) 2 A b) p 5 ± = 320 W; p 25 ± = 400 W; p 70 ± = 280 W; p 10 ± = 360 W; p 8 ± = 800 W c) 2160 W 2.21 a) 60 ± b) 2000 W 2.26 a) 0 A b) 60 mA c) 240 mA 2.29 v 1 =− 50 mV; v g = 6.25 mV Chapter 3 3.3 80 W 3.6 a) 16 ± b) 6 ± 3.10 33.75 kV 3.13 i g = 12.5 A; i o = 2A 3.16 26.67 ± 3.20 a) 66 V b) P R 1 = 1.88 W ; P R 2 = 1.32 W c) R 1 = 17,672 ± ; R 2 = 12,408 ± 3.26 v x = 16 V; P = 75.2 W 3.32 0.1664 % 3.36 27.03 % 3.46 300 mW 1011
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1012 ANSWERS TO SELECTED PROBLEMS 3.51 2 k ± 3.54 a) 120 ± b) 60 W 3.56 a) 4 A b) 1.1 A c) 6 V d) 2500 W Chapter 4 4.2 40 W (absorbing) 4.5 10 V 4.9 v 1 = 100 V; v 2 = 20 V 4.13 1 A 4.17 a) 2000 W b) 35,000 W 4.20 26 V 4.26 602.5 W 4.30 a) i a = 9.8 A; i b =− 0.2 A; i c 10 A b) i a 1.72 A; i b = 1.08 A; i c = 2.8 A 4.33 a) 1.0 mA b) 8.5 mW c) 0.225 mW 4.35 98 W 4.38 600 W 4.44 2 A 4.51 a) 3 mA b) 345 mW 4.54 a) 1 A b) 1 A 4.56 v Th = 48 V; R Th = 16 ± 4.59 v Th = 52 V; R Th = 6 ± 4.62 i N = 8 mA; R N = 10 k ± 4.65 a) 150 k ± b) 1.56 % 4.69 v Th = 0V ; R Th = 18.75 ± 4.74 R o = 2.5 ± , 22.5 ± 4.77 a) 2.5 ± b) 2250 W 4.80 3.77 % 4.82 a) 35 ± b) 505.4 W c) 21,364 W 4.84 25 V 4.87 i o = 2A; v o 136 V 4.90 a) 4 A b) 160 W 4.96 40 W 4.98 0 A 4.101 v 1 = 37.5 V; v 2 = 105 V Chapter 5 5.2 200 µ A 5.4 a) 400 mV b) 6.8 V c) 20 µ A d) 111.67 µ A 5.6 3.1 mA 5.8 a) 0 σ< 0.2 b) 200 µ A 5.11 a) 415.38k ± b) 650.37 µ A 5.13 0 R f 75 k ± 5.17 a) 108 k ± b) 270 µ W 5.22 a) 7.56 V b) 3.97 v g 3.97 V c) 35 k ± 5.26 a) 56.3 mV b) 114.3 k ± c) 80 k ± 5.29 R b = 1200 ± ; R f = 2000 ± 5.33 v o 1 = 15.85 V; v o 2 = 13.6 V
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ANSWERS TO SELECTED PROBLEMS 1013 5.40 a) 39.997 b) 4.02 µ V c) 8000.644 ± d) v o /v g = − 40; v n = 0 V ; R g = 8000 ± 5.42 23.89 k ± Chapter 6 6.3 a) 100 e 10 t ( 1 10 t) mV b) 18.32 mW c) delivering d) 1.83 mJ e) 3.38 mJ 6.5 a) i = 0, t< 0 i = 16 t ,0 t 25 ms i = 0.8 16 t ,2 5 t 50 ms i = 0 t ,5 0 m s <t b) v = 0, 0 v = 6 V , 0 t 25 ms v 25 t 50 ms v = 0, 50 ms p = 0, 0 p = 96 W t , p = 96 t 4.8 , 0 t 25 ms 25 t 50 ms p = 0, 50 ms w = 0, 0 w = 48 t 2 , 0 t 25 ms 4.8 t + 0.12, J w = 48 t 2 25 t 50 ms w = 0, 50 ms 6.7 a) 8.75 e 2500 t + 18.75 e 7500 t V b) 152.44 µ s 6.9 a) 2.77 ms b) 64.27 V 6.12 1007 W, absorbing 6.16 a) 250 µ J b) 19.31 mJ 6.18 a) 1.25 µ C b) 5 V c) 2 µ J 6.21 20 H 6.25 5 nF, with initial voltage of 10 V, positive at the bottom 6.27 32.19 ms 6.31 a) 54,031.25 nJ b) 44,031.25 nJ c) 10,000 nJ d) 18.51 % e) 1.39 ms 6.35 a) 60 + 5780 e 4 t 5840 e 5 t V b) 0 V c) 960 + 92,480 e 4 t 94,400 e 5 t 92,480 e 9 t + 93,440 e 10 t W d) 960 W e) p 5 ± = 720 W; p 20 ± = 180 W; p 60 ± = 60 W 6.39 a) 0.85 b) 28 mH c) 7 6.44 v(t) = 1 3 v s (t) + v( 0 ) , so moving the button has no effect on the change in Chapter 7 7.1 a) 25 ± b) 12.5 ms c) 312.5 mH d) 2.5 J e) 10.06 ms 7.3 33.33 % 7.5 a) i 1 ( 0 ) = i 2 ( 0 ) = 0.2 mA b) i ( 0 ) = 0.2 mA; 0 ) 0.2 mA 1 + 2 + c) 0.2 e 10 6 t mA, 0 d) 0.2 e 10 6 t mA, 0 e) The current in the resistor can change instan- taneously. 7.7 48.64 % 7.9 a) 200 A b) 220 A c) 307.6 µ s (6 mH, not 2 mH) W J t t +
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1014 ANSWERS TO SELECTED PROBLEMS 7.12 a) 625 nJ b) 625 nJ 7.14 a) 2 e 25,000 t V, t 0 + b) 80 nJ c) 59.9 µ s 7.19 a) 180.34 mH b) 93.75 % 7.22 a) i = 15 e 125 t mA, t 0 + v 1 = 60 e 125 t + 15 V, t 0; v 2 =− 15 e 125 t + t 0 b) 5625 µ J c) w trapped = 1125 µ J w diss = 4500 µ J 7.25 a) 125 × 10 6 A/V b) 180 e 1000 t V 7.28 a) 10 e 5000 t mA, t 0 + b) ( 20 3 e 5000 t + 320 3 ) t 0 c) 2560 µ J 7.31 312.5 e 500 t µ A, t 0 + 7.36 80.47 ms 7.39 a) V s = 80 V; R = 20 ± ; I o = 8A; L = 0.5 H b) 17.33 ms 7.42 3.67 + 6.33 e 250 t A , t 0 7.44 60 + 90 e 2000 t t 0 7.47 a) 480 e 10 t t 0 + b) 4 e 10 t + 4A , t 0 c) 6 e 10 t + 6A ,
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This note was uploaded on 10/27/2008 for the course NNNNNNNN nnnnnnnn taught by Professor Nnnnnn during the Spring '08 term at Punjab Engineering College.

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Electric Circuits (6th ed) by Nilsson (Answers Problems) -...

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