# CH12,13 Advanced.docx - CH 12 13 1 In a town 30 of the...

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CH 12, 13 1. In a town, 30% of the households own a dog, 20% own a cat, and 10% own both a dog and a cat. If we select a household at random, the chance that they own a dog or a cat is 40% This answer is correct. We want to find the probability of owning a dog or a cat, which we could call P(A or B). Since we have the word "or," we need an addition rule. These events are not disjoint since there are 10% of households that own both a dog and a cat, so P(A or B) = P(A) + P(B) – P(A and B) = 0.30 + 0.20 – 0.10 = 0.40 or 40%. Text reference: section 13.2. 2. A group of college DJs surveyed students to find out what music to plan for their upcoming parties. Thirty percent of the students preferred dubstep, 25% of the students liked trance music, and 20% wanted to hear only house music. Fifteen percent of the respondents selected both dubstep and trance. The proportion of students that preferred either dubstep or trance is calculated by; P (A) + P (B) – P (A and B). 3. Event A occurs with probability 0.2. Event B occurs with probability 0.9. Events A and B: cannot be disjoint.

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• Fall '09
• WRIGHT
• Advance Homework, Chapter 12 And 13

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