Test 3 Key - Test 3{E3 Name Printed No calculators etc Show...

Info icon This preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Test 3 {E3 Name - Printed No calculators, etc. Show your work on #2—7. Circle your answers. Put all work on this test paper. Maximum score = 73 1. a) Let f (50’) be defined on a domain D in R3. Let f0 6 R3 and assume that D contains points arbitrarily close to 330. Let L be a real number. Define precisely w) lmfm=L 7:“ «a e>o am we 5‘» a Mar )7 M D M2 Hui-KIM? 74in H307)" Ll <€ b) Find the limit if it exists. If it does not exist write “DNE” (no work necessary). 4_ 4 (5) ( iinio 0) :2 + :2 @ (Ely "—’ 7 7. '2 Z t1 2. Jo x'l’vb' s. 2‘ ““9”“ :_ 21109?” 2. Let f(:1:,y) = $312 — 2m a) Find fiflx, y) (3) *5 \7 H m> ; b) Findfl’so that Dfif(2,1)=0 ~—3 —> .\ W9 v H2 o = <4 LI> V.F[2)l) ~ (,3: 0;? H22!) ’ ) f we vii“ a. unli‘ ch‘l'v-L C3 ”Vi/fl (7f..<-—Ifi> :0 o r _,_\ <flfl> :: < :1... —L‘ > flit: I 7““ U“ “Apt! a?) «)1: <1?! 55‘.) Absent/Cr c) The surface given by the graph of f is sliced perpendicular to the x—y plane at (2,1) in the direction towards the point (5,4). Find the equation in R3 of the #1:,“7 tangent line to the cross section thus obtained at (2, 1, W ,1. (CO rW/’ (7) ~——~3 A} v 3 <9)” * <ZH>= G) D —3 “—37— 10.? u~ V = <3L;)Jfi> W“ 1757” 3. Find the equation of the tangent plane to the surface 3:2 +22 2 x+2y+32 at (3, 2, 1). LIJQ— ?(XfiLQ); X‘X +2.2-A3%_2_gj flcjmfkc4 I; fitXfifl-‘EV-e [S le?)l)l) (7) 4. Find and classify as local max, local min or saddle point all critical points of - - _ ._Z Z f(m,y)=:zs1ny 1n D—{(w,y). 2 <y< 2} 2 <O/6> FF load f+ U <0)C>> ‘ ‘P(D’ O) :0 Prison/tam #9} 10:21 X ”5° “$31”; + 5. Let S be the surface given by the graph of z = 1 + 11:2 + 4312. Let D be the region in the :r—y plane bounded by y = a: + 1 and y = $2 — 1. Express as an iterated double ) integral but do not evaluate. . (2 ) 3 a) The volume of the solid lying under S and over D. D , (7) WA “mac/i 6. Find /D/e ”32—1/2 dA whereD= {(113, y): w 2+3123 4} mfkngziz [3:144 CboFan/xq‘j'ea, 271,6122 jfje rfir1’9& :2] iérz‘) 0 £& 7.] f(x,y)dA=/e:([lnyf(x,y>dx)dy D a) Sketch D (label key points) ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern