exam1_solutions - KEY I’HY 311’1‘2 September 23 EUUH...

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Unformatted text preview: KEY I’HY 311’1‘2 September 23: EUUH Name {print-3d): ........ ...................... .. Signature: ....................................................... _. EXHJII 1 — Unique IlllllllJHF $1735 1n5l.rur~.l.Inns: :- NOTICE: Fur HH pr'rJhIHrrlr-x rm this HKHIH.:-r'1:-IIH}IIIII|1111HSHEHEIHLT— Inllilfilfiu. Alain? igrmr'n Mir l'tlFaiHIHIH'JJ in H.” prujr—erttihi 111r:|.im| prrihhlnm. II IVE! Hutch LexLlnmim. 01' fiiulihu' flir'lh' urt: pecrmiil-euf. Tun |||2|.I'5.-' 115+: H t:2l.ir:llhtl.nr. I USE; the smut-Ion mmwru‘ ahmi. LO prrwir‘lr: E-hr: Erru-r'rvru'ts. 1Ir’k'rrih: :LIuE huhhlt-i 3mm name-2 mul U'i' BID carefully. Sign and dart: it. Markrrnll'fican1rml urging a. #2 p{:1u:il. - Jury quwtiuns you ma}r have abnut the test must he. directed 1.0 1.11m infiiruumr 1“- TA 1m CDIH-“(rl‘fifli-iflnfi flilt'lIIIL'JI' UUHELHLM'ELll'r-‘fi wurl-z H11.”- ]HI['[|!lII!.L£-!il. I Some infflTJImt-ion that may hr“. useful 1F: 1211'I.'n-'3L‘1L':r'1 rm |.11I.': luHL pugr: “1' this ]1H-lHlHIJI.. YUM 1114:1354-r nm: malt. quest-ions Erhnul Lhr: infirl‘flml-iun U11 l-h'LH pagrn Mm. iJ' }-'[Jl[ drama-M |.}Ir-! page! from t-hr- l1m1dout. you must return it with 1.11:; 11:51. 01' 1.1m hmu‘lmn. :11. I.lu—: mu] “1' Hm “Ti-$1.111. I Um: |.11L: béwl». hirlm “1' |.11H men pé-lgifi :13 Elu‘flltih “HEN-11' J'm' [I:1.]lillL'—l1.i1:-IIH H3 Hundred. 4- YUU MUE'T‘ TURN 1N THIS Uvail’LETE EXAM HANDUUT [A LL PAGES}, INCLUDING THE EUUA’I‘IUN SHEET} AT THE END [IF EXAM]. PRINT Y0 UR NAIflE AND ALSU SIGN THIS FHUN T PAGE. 60735 1. 1'1 |11'11_j1-:1:1.111-1 111 1111111. 11111111111111 111111111111 1111.11 1111 11111.1111 1111111111 1:“. 15111 11-11111-1111111? 1:11.11 1111 11311111111. T1111 111'11j11111:i11-1 11111.1:11111-1 11.111111111111111“ 11111111111 H 1111111111 11 1111111111 11111113. 1:111 .11. 1119111111111 1111111.. 1111-! 111'11j1—11:1.111-111111-1 1.111-1 111111114.11111111.]1111111111.I 11111 111 1111111111 11.1. 1111 11113111 15” 1111111111 1.1111 11111121111111] 1.111-1.~.1-r.1'1.111. 11311111. 111111] 111.1. 11111 11111in11111111 height 1111111111111 1311r 1111-1 projectile 1111 11111 11111111111 1111111.? Fired. Surf: Li :7. LL _ €- ~er1b1 111:1 5” fmfifl '- 11:111-15- 11-1 111.11 1111...“) :11 __ “a E I _. 3% a 1.1.. 11 2 ~ 1361 1.115. 1111 11111113 1.11 11113111- .8 mflA 5110+ 1—1" 9L ‘ U1?" :' ‘11-'14 bin 1.. :1"; vi ; DIE “figs-I- '11-'1- . _ _ _ 1-: HEW—“:E- . . 11. 151.1: 11. 11111}: 11g11t. 11 111133111311". 113110111113 .11 11.1.1 11115 1311111515 11 11.3 11 51.111111 1111111 11:111.. 1111-: 121112111111 1.13.1919. 111 a cam-111.111 11111111131 111111 11111 1:11.1- 11115 11111111111111 0.1313111011111011 3.1.1 11115”. What will 1.11: 1111: 1531111111 1311' 1111: 1:111r 11.1; 1111: 1115151111 111131111 it cat-11111111 1111 1111111 1111-: him-1:11.“? 112111; “a 111“ 11* 11 1111 13111.15 1)“ 11:11:15 1 01'0"“15' ; Q 111116 a ‘5'} #191111 11:1 11111-1 waif —_ g. [11:1 24 1'1'1111-1 1:1 1111 111111: 111} 11111111 111 111111.111 (14“[1’12 ‘14:. '1 Lana-t ‘1' £111, {TL 5 ié-fi'wfa'tl- ahikL&}=-Afib+ fighti. light: 5 (gig “El:in }er:JLikt 1:1 {:11 (:95 a) “MFG-1’5)": 1111111111191) 5'13-C'M1’rii1géa) 5 13 “115- 3. 1310C1i5 3'11 11.1111 B 1111': 1:111u11:1:11:1'1 1131' 11 1-111'111g. 111111 1111111131 111-; 111111111111. 11111: .151 111111 111111-111 m. 111111 11111111; 1:3 111111 111111111 2111. 11.11..l 111111:1-: 1111-1 111111111 11111111111111 11111.1. 11111111111 1'11] 115511111119 that 1111': 11111113 111.1111 1111111131 11111 11111115111113 111111 1.111-11 1.1111111 1111*. 1111 1'1'11:1 111111-11 1111111111. 1131111111. 11-1 1111:1 11111911111111?1111.111! 111111111111 111 1111-1 11111111111J 11 1 an: L 3.0 mfg"— 11} I11] 1 .11111 11131111111111“ my 1_1|‘— JII— 1:1" I- 1 I: 1111; [11] 11111 1 H_.._-_.5.[ 11 none 111 11111111: 60755 4. Snimnfic :1 -- 13"‘(T-m. where :1 has diinensinne lif'l', l] 11lle dimenaiene l'v'II.-. and (3' has; diiiiensieiie l'vngf'l'. where M represent-5 the dimension 1117-1551 L represent-e the dimension length, and "l" represent-e ’rlie diixieneinn time. Then the exponentai ill and ri, respectively {i.i‘:.. m l'ii'e'il n amend]. haw. the values: L __ W1 1. T1. l,l f -“ (ML) J"'_N"-_1': ll x —'| l T 631 =' L? l=m+ln I'd: —'l~ —l -_ ; kl). N: a “4‘” =37M=Hn ¢M:_ [53'3" 7"l=e=n finial fie.) urine. of these i- -.“.. (51—, ML?— L T ML. T :" 3:. 11' If: = IE —- i-Lml iii-tillini' i-‘Hllllill' in mm. Hit-Ill: r_,_ i A . . _ _ _ _ lA-B|:|Al-lgl {is} .4 and H lllllfil. liH parallel and lillllll. in Lllf'. E'ATHII‘. llll'fllilllili _ . .. :. ‘-'* -‘ -—-";‘»*[bl 1'1 and H must be parallel and point in the opposite dii'eetieii Ltd J" 1.5:! . '. .. _‘ , - . . ,. —‘ a (a) a: and If uni-:1; bL Iierancliculcn E A g I E. I -;. ,— I 8] [ll] :1 Hull 5 lllllril. him-'1: llllllfll llll-Lgflll InlnH J _._ a r A TE wl none hf t-l'iL-ee '-'—-'F———} hflR‘fi-l—i *— lM +131 —3‘ E5. Elm-ks A and 13 are connected liy a Sit-ring end pulley 21:; Shawn. Bloc]: i‘i. with 111.155 20 kg. i'eete without moving on an inclined plane. The. inclined plane is inclined at. an angle 1'! — Lil‘lfl fl'um the herlmniel and the coefficient of 5l-lLl-lt' friction between the plane and The block 15 0.50. Assume the string and puller.r are limenleefi, the pulley i5 lriehienlefie, and that 5’: -- 1L] 111E332. If the. males of bleak T5 is fil‘LllLllL‘t' than ll. certain i-“zilne1 block A will slide down the inclined plane. “11.11: is the value of my helmv whieh lileelc A will elide dawn 1.1m. incline? r—‘elal L3 ke {h} 3.1] kg . [e] 18 la; "P {{1} 11kg (H) 1.": kg Black F :I'J'I’Pl fl} '9 I . _, handle? 5 Eiflflkg‘ El ' Tflws‘fl éiLmAfime Wile; 6035 . . . . .- 'l 7". Starting Inrrrl Heel.~ H, [ii-LIT amelel'ulee WII-ll [:[JHHI-E'LIII z-Ix'.t:elt-:['Hl.mu dillmlxh‘ l'm' FLU H~ the“ lmrTIt-hvrlinl't‘l}r litegirH-a decelerating with HE‘IrlHlJ’Hll. untnxlnralinn —-"l.'|'ln:LI.-".u.J 1:11I.ll il. HlEJpH. During l.l]lH rrI:Jl.h:-r|. ll'lII-E t1:-|.[' [nu-wee in 21. HIralghl-llrle (lire-Attica“. Huw [HT dues l.l]t‘. :“r-Jr 1" r = re. + em: + be? = {Hee‘tlfeel‘f = See. trawl. —-~:} Iii-L] lfll'l m Um : l a r . _. tbl EUU m 2‘ 1"!" F v“ +a'il F Flak-MEG") '— 10 “"l'5 (c) iflflm LI); —_ 0 .: kiln-4L 61:4“; 57;, £1. :_ {lei : Fgfiomfg I; r. {:l) 5mm 1' a1- .thmhi. L35 1- :— ‘l' U -— IL :_ " 1 [Cl In :F D:- o'L-E' + I. flirt-1 'l.’ 94:5 1,. 1—16. 4mf-‘L)(S-5) c lGC m 8. rl‘he components of two vectors 431' and 13' are as fellows: .ler — I]: fly — —l, A: — i and Ba; — —3_. By — U: Bz — .15. When these two veeterr; are. located with their tails at the same point. what is the angle between them? e) are EEK-E = leilelme e e“ 1M er *5“ "51*4fir_—"+ere. Le {fill 90° A .1 [el IIHJIE' :Jl' thee-m :— AJE EX Jr ‘61 Ar AEEE 1 (QM-'3} ‘l'f’llfflj 'l'fllli) 'r— 3; E- 77 mime :— ;. 3 =-‘? me i E; #5 :e e we: {ii-l r em" ll'. in n. gfllmiy far. I'm away, :1. Hpaue thp he in Imll'm'm ::ir-:-.ul2~1.[' mutinn HJ'lhllrltl Pi large planet. The fipt‘fl'l l'Jl- lllL‘: enact: :illiiJ ma iL mums in. the: nimulm m'hil. ll-i EDITH-I mfr; 21ml l.l1|.::l‘l-‘lfllllHE'Jllllf: Hpfld‘ftl HllllllH ur'lrll. lh 4.fl X l'll". m. The HI:t'.[‘.l+'.]"r]llIIIIII HI' the 51mm elfi]: ix: 2L] LU 111,35“ luwmtl the plum-:1. 11:1“EF— :3] anffipgulfll 2 v5}: (bl LU 111.2%:2 away frem the planet _._., = (iamfll‘lfll [c} 11.1 mfe2 away from the planet T " Ll": 1(fine {4 3.0%,?) .—__‘_:‘.,I::l::l {Ll mfg-5 mural-:1 the. planet 5 H}- [m 'L- l {e} unlnmwu: since we. do not, know ,r; at the surface 01' the 1:: met '3 :1 ml mfg" leek“ '4 the inland-l 60755 ll}. Two identical boxes of mass 412': which are connected together by a string~ are sitting motionless on a frictionless inclined plane. 'l'lie boxes do not. slide down the inclined plane because a force F, direct-ed 11p the inclined plane, is applied to one of the boxes, as shown in the figure. What is the Iriagiiitnde of the tension in the string between the boxes? Bax i: {Ill F 2 If,» T 5 Me a {bi 1 ,- 5:; r3» Box a: r . r” ‘ 121‘ e , [e] 2e Ma. r T so Mr; e 1T r- e [e] inikiiiwrnJ sirli'n the angle. of the. inclined plane is not. given .1: g Tim. problem is no i;¥l—esee-t 'ttwn "Ham! _ were, oo at horieuetcd 5m lacs. 1].. A. cannon fires a projeetile as shown. The dashed line shows the trajeetorgg iL would Follow:-r in the absense of greeting! and the solid line shows the actual trajector;r lie.: with gravity]. Points E'Iril N! O. and 1" correspond to the position of the projectile at one second int-ertels. Assuming g — it] inf-“s2. what are the lengths X: "1’1 and E? (a) 5:. n1: 20111.3Um 1:Ilr: of math} ii 111._ Eil Ell, 45111 [cl lLiI in! 31G in! [ill in {d} 5111! 151n,35 in (H) ill in! 5H] m._ Fm lll near—W es 5': 1 — 5) [Efikijil'jj‘l E '5“ “l “l -" ia Ate-it: o‘ 113m mi is) i two new. IE. A projeerjle is shot. into the itir 1with initial spied llIID nifs at an angle h‘tl‘“ above the horizontal. During; its flight {i a, before it hits the ground}! what is the minimum speed of the Iimjctmilef?’ 1.} fir” amid-ll m 111er The. i'flmimaes speval occurs- when iii} iii-l Hill's 'H'“ Vriti'ide-Ll Lvraffi'ocn-l ot’ ‘l'lfie. +._.;.{e'] {allmfs' Silk; 15 “ll—5'“ imi- "hl *jl'm’i‘ch-Heaal film; ._} m] m me'u Jemima-Hon. “ V ’9‘ . I... :3 1 I to] HTnifs This occurs gL-t' H”: Fri-lacking .meHrt as -l-a—W Us 15:11. 9 Fl flu: :' U, '50“; E} I {ligDMIEJIHiy'jfir-Iyfl" : SD Irv-fa 60?55 13. Blocks A and [11 am nonnootod l1]; :1 String and pulley :15 shown. Aasmne that the strmg 11ml polio}; 1m: moosloss, that tho outfooo 15 friotionloosa and that oro no oti‘m‘r frictional effects, and that .qi — lf]1n_,e's:2.. II the moor: of block 13 is half that of block A {1.0., mi; ; mjgfifijl, what is tho magnitudo of the oocolmatioh f tho hEool-zs'? {a} 35 mg: Emu-11: MajoHuJ-L‘ r 2 1 —,‘-"[h] 3.3mm? 5F occnhtru’dofi r 1‘“ 1M“ ' “"35” fifth: Fat I T" WM" (c; Mutts? FE" hath “Mb 1' H04: 6 my mme a]: 5 F , - M . _I “is o 1' 3.: K 1:9.) none of theme 1. 173’? —- M :1 egg, .._._ ” 1 .- -:.- J? (.1. 4. 3 I : Flt-Ma} J. 1? + 3 '" 4.1 = 5 fl = L". l t Id. :1 pomhflum hob is hold at an angle {a' = 30° from the vertical by a horizontal force. I?! as shown. The 111agn'1tude of I" 15 SUN. t-‘lu'hat is the mass of the hob? = T-mfifi' -—' “14:- E‘. «1.51:3 '5 H- IHEHH: :: :, fluff WE —‘>[h) 3.171% The: offlifié Effie) mag; '33] H Jig F: 5' Egdxlly a1:fgfi.t Tu: " Toll-1.19 1'— F [it] “W: by the hookantfll 5 3‘1 - my W 91 kg ww-mm or 4o. mm a ' ‘ M3 or. E 1-; m a r -\. .-\. n I 12"? 4 I5. Tho. vahu! tin 'x. :4 1:} iii: J “I. :: 50M —- ' D “N 31“ : "‘ Hrfi—FJ— Ti 1 3 t 1 (WW) 'I .IN Ira] I III: =- 0 Lficmméf; fix {I/ “T fit? 3m 0; i E} 5 [d] .i to] 1% 60%5 SHIRE Equatimlfi fm' Exam ] Hinflfl” — — flfiflfl; i'JIIIH Fifi” - — flfififi; |.2-|.l:l.":nn — — — U57"? sin-4.5“ _ 413m; “3545c . _. [1.TUT; tan-15° _— 521-13: ; 1 . J'T . . I a: 4—- mnefina —. $42-5- = 0.3136; mstiU“ _ t _ 0.5m; taflfiUc' _ — 15:; — 1m For vectora AI — Amt + £13,3— Hal-II: und f1" —. HI]? | 3ij - Bfit: |£k—A—fififi+fifikflq i-fi—AHmmH—Afifi+Afi%+Aflfi JEE=L%fl-flfiflhflmflfiqhmfi+pfifi—AJME ia‘TH fi| - Afirfinfi'. 1701' El funntitfl't of that form f (1": — 5:31;". when: n. is an intngcr. if I 'I'I' — _ “(l-I: rL-J.‘ and [HIM-x = a lx'1"1+ C. n. -- if a particle’s pmitiun is ram-emuml by F - fit} 1:, 031'" I d _ __ riff _ fin?"- , _ E” M: a— [fit — “it? '1‘11nrtri'm'c! MEL) — rJ.;,_IL£}rFt -|- (3' mm] unlit} 'rJ:.:I;£}r.I.'t — C, and similarly Frhr' 1:— m‘u‘i S-Lllillllptfllt-llllfi. For a, constant mmflomtinn ii. | H flu=m|%u m3 mm tm—m+m r V I, th-ut! '5‘], mul 17".” 21114. LhH pnxil inn and waltufiw at L'Emrr. ne'- — fJIl t't‘fipr.‘.(_¢h't:‘i}’. Front}! {ailing t'fil'thffll-h Hum the. EHIHI'H surfam m:w—*.1¢*.i'a1.+a {Inwnwztr-HH with y — {H13 “II-".552. 1 - . . I 3 ' 1'0]? “115 Exatnf “HE: Hm appr'nmrrI:I.l.L-:m LIIHI. 5r - m min; . Ullift'n‘nl L:iI'<;u!i-:I1' [ILHHUELI rt T'IZIIIT'E and 'T fluff}: Newton’s Second Law: 1" : mfif. Stat-it: friction; “IL-g :5 MEN; kinetic: Iridium; f}, = mu"? [where ."'I.-r iH Hm rrIHgIIiLIJth! Hr Hm. normal farce}. ...
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This note was uploaded on 10/27/2008 for the course PHY 317k taught by Professor Kopp during the Fall '07 term at University of Texas.

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exam1_solutions - KEY I’HY 311’1‘2 September 23 EUUH...

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