Project 5

# Project 5 - that the relationship between the level of...

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3.577 7.154 20.269 31.000 n't Know 0 1 3 4 0.462 0.923 2.615 4.000 sy 1 1 7 9 1.038 2.077 5.885 9.000 rd 2 3 3 8 0.923 1.846 5.231 8.000 l 6 12 34 52 6.000 12.000 34.000 52.000 ll Contents: Count Expected count arson Chi-Square = 4.347, DF = 6 kelihood Ratio Chi-Square = 4.674, DF = 6 Tabulated statistics: Gender, LowFat Rows: Gender Columns: LowFat No Yes All Female 15 22 37 Male 10 5 15 All 25 27 52 Cell Contents: Count N Sample p 25 0.400000 27 0.185185 p (No) - p (Yes) difference: 0.214815 und for difference: 0.0120998 ference = 0 (vs > 0): Z = 1.71 P-Value = 0.044 Chi-Square Analysis Is there a relationship between the level of difficulty of a class and what area students sit in the classroom?

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Variables: ClassDiff (Categorical) = p 1 SitArea (Categorical) = p 2 Hypotheses: H o : p 1 = p 2 H a : p 1 p 2 Conditions: at least 75% of the cells have an expected count greater than 5 x 2 = - Observed Expected2Expected = 4.349 p>.50 The p-value is greater than 0.05, so we fail to reject the null hypothesis and conclude

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Unformatted text preview: that the relationship between the level of difficulty of a class and what area students sit in the classroom is not statistically significant. Comparison of Two Proportions Is the proportion of female PSU students who maintain a low fat diet greater than the proportion of male PSU students who maintain a low fat diet? Variables: Gender (Categorical) Low Fat (Categorical) Hypotheses: H o : p 1 – p 2 ≤ Ha: p 1 – p 2 > 0 Conditions: n 1 * p-hat 1 = (37) (.595) = 22 5 ≥ n 1 (1 – p-hat 1 ) = (37) (1 – .595) = 15 5 ≥ n 2 * p-hat 2 = (15) (.333) = 5 5 ≥ n 2 (1 – p-hat 2 ) = (15) (1 – .333) = 10 5 ≥ The p-value is less than 0.05, so we can reject the null hypothesis and conclude that the proportion of female PSU students who maintain a low fat diet is greater than the proportion of male PSU students who maintain a low fat diet....
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Project 5 - that the relationship between the level of...

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