sol3 - HOMEWORK No. 3 SOLUTIONS ECE3040 Problem 4. JP = qp...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
HOMEWORK No. 3 SOLUTIONS ECE3040
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Problem 4. J P = p pE qD P dp dx =0 E = D P μ p 1 p dp dx = V T d ln p ( x ) dx V T = kT q V bi = Z x n - x p Edx = V T Z x n - x p d ln p ( x ) dx dx = V T ln " p ( x n ) p ( x p ) # p ( x n )= n 2 i N D p ( x p N A V bi = V T ln " n 2 i N A N D # = V T ln " N A N D n 2 i # Problem 5. Compute p ( x ) from the equation for the hole current density: J P = p pE P dp dx E = V T d ln p ( x ) dx dV dx = V T d ln p ( x ) dx Integrate: V ( x V T ln p ( x )+ c (1) Use boundary condition V ( x p ) = 0 to compute c : 0= V T ln p ( x p c c = V T ln p ( x p V T ln p p 0 Substitute into (1) and solve for p ( x ): V ( x V T ln p ( x ) V T ln p p 0 = V T ln " p ( x ) p p 0 # p ( x p p 0 e - V ( x ) /V T Compute n ( x ) from the equation for the electron current density: J N = n nE + N dn dx E = V T d ln n ( x ) dx dV dx = V T d ln n ( x ) dx
Background image of page 4
Integrate: V ( x )= V T ln n ( x )+ c (2) Use boundary condition V ( x p ) = 0 to compute c : 0= V T ln n ( x p c c = V T ln n ( x p V T ln n p 0 Substitute into (2) and solve for
Background image of page 5
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/28/2008 for the course ECE 3040 taught by Professor Hamblen during the Spring '07 term at Georgia Institute of Technology.

Page1 / 5

sol3 - HOMEWORK No. 3 SOLUTIONS ECE3040 Problem 4. JP = qp...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online