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EE103hw6%20sol

# EE103hw6%20sol - EE103 Spring 2007 Solutions Homework 6 1...

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EE103 Spring 2007 Solutions Homework 6 1- Find the indicated currents in the circuit using nodal analysis a) The node equations are (I5 is the current in the resistor between the two networks) 125 345 10 0 20 AI I I −−−= −−+= 111 2 221 2 10 10 20 10 2 30 50 10 VVV V A V A =++ =+− 12 10 0.25 0.1 2 0.1 0.154 AV V V =− + solving 1 2 61.64 53.09 VV = = The currents can be calculated as 34 61.64 61.64 6.164 3.08 10 20 53.09 53.09 1.77 1.06 30 50 I AI A I A == ΩΩ

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b) Using nodal analysis solve for V x The node equations is 10 0.1 0 40 10 20 xx VV A V −− =⇒ = 2- Find i 0 and the power dissipated in each resistor in the figure Using nodal analysis In the supernode 02 1 20 ii i −−− −= In the other two nodes 2 12 240 20 i ++= =+
The currents are () 01 12 22 3 6 3 56 iV V A = = =− = Solving 1 2 3 7.12 12.9 11.7 VV = and the powers are 2 2 11 1 2 2 2 2 2 32 3 3 7.12 6 304.16 12.88 3 497.68 12.88 11.69 5 7.08 PVG V S W W PV VG S W == = = ⎡⎤ = + = ⎣⎦ 3-

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EE103hw6%20sol - EE103 Spring 2007 Solutions Homework 6 1...

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