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Unformatted text preview: 8 9 104321 1 2 3 4 t y y ' = k (A  y) A = 1 k = 3 “A” changes the height of the graph where “k” changes the rate. Comparing to real life, A is representing equilibrium solution where temperature has no change in a time. On the other hand, “k” is representing the rate of change which determines how quick the object hits the equilibrium solution. Exercise 2.6 a) dy/dt = k ( A  y ) , y(0) = 7 b) “A” should be 40°F c) at about 15 hours 2 4 6 8 10 12 14 16 18 2010 10 20 30 40 50 t y y ' = 0.3 (36  y) d) about an 2.8 hours Thus 15 – 2.8 = 12.2 hours will be saved 2 4 6 8 10 12 14 16 18 20 5 10 15 20 25 30 35 t y y ' = 0.3 (68  y)...
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This note was uploaded on 10/29/2008 for the course MATH 20D taught by Professor Mohanty during the Fall '06 term at UCSD.
 Fall '06
 Mohanty
 matlab

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