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Unformatted text preview: Jolley, Garrett Homework 4 Due: Sep 19 2007, 3:00 am Inst: R Heitmann 1 This printout should have 23 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points Find the value of lim x 2 f ( x ) g ( x ) 2 6 f ( x ) 1 g ( x ) when lim x 2 f ( x ) = 8 , lim x 2 g ( x ) = 3 . Correct answer: . 509804 . Explanation: By properties of limits, lim x 2 f ( x ) g ( x ) 2 6 f ( x ) 1 g ( x ) = lim x 2 ( f ( x ) g ( x ) 2) lim x 2 (6 f ( x ) 1 g ( x )) . But again by properties of limits, lim x 2 ( f ( x ) g ( x ) 2) = lim x 2 f ( x ) lim x 2 g ( x )  2 , while lim x 2 (6 f ( x ) 1 g ( x )) = 6 lim x 2 f ( x )  1 lim x 2 g ( x ) . Consequently, limit = 24 2 48 + 3 = 26 51  . 509804 . keywords: limit, laws of limits 002 (part 1 of 1) 10 points Below are the graphs of functions f and g . 4 8 4 4 8 4 8 f : g : Use these graphs to determine lim x 3 { f ( x ) + g ( x ) } . 1. limit does not exist 2. limit = 3 correct 3. limit = 2 4. limit = 6 5. limit = 1 Explanation: From the graph it is clear that lim x 3 { f ( x ) + g ( x ) } = 3 . (Dont forget that for a limit to exist at a point, the left and right hand limits have to exist and coincide. So determine left and right hand limits separately and use limit laws.) keywords: limit of sum of functions, graph, limit 003 (part 1 of 1) 10 points Determine lim x 3 n 3 x 2 3 x 1 x 3 o . Jolley, Garrett Homework 4 Due: Sep 19 2007, 3:00 am Inst: R Heitmann 2 1. limit = 3 2. limit = 1 2 3. limit = 3 4. limit = 1 3 correct 5. limit = 1 2 6. limit does not exist 7. limit = 1 3 Explanation: After simplification we see that 3 x 2 3 x 1 x 3 = 3 x x ( x 3) = 1 x for all x 6 = 3. Thus limit = lim x 3 1 x = 1 3 . keywords: analytic limit, difference rational functions, limit, common denominators 004 (part 1 of 1) 10 points Determine if lim x 0+ 5 (4 / x ) 5 (1 / x ) exists, and if it does, find its value. 1. limit does not exist 2. limit = 1 4 3. limit = 4 correct 4. limit = 4 5. limit = 1 4 Explanation: After simplification and cancellation 5 (4 / x ) 5 (1 / x ) = 5 x 4 5 x 1 . On the other hand, lim x 0+ x = 0 , and so 5 x 4 5 x 1 = 4 by Properties of Limits. Consequently, the given limit exists and limit = 4 . keywords: analytic limit, quotient radicals, keywords: 005 (part 1 of 1) 10 points Determine if lim x 3+ p 16 x 2 exists, and if it does, find its value. 1. limit = 3 2. limit = 0 3. limit does not exist 4. limit = 10 5. limit = 4 6. limit = 7 correct 7. limit = 3 Explanation: For x near 3 the inequality 16 x 2 > holds, so f ( x ) = p 16 x 2 Jolley, Garrett Homework 4 Due: Sep 19 2007, 3:00 am Inst: R Heitmann 3 is well defined for such x . Consequently, by Properties of Limits, the right hand limit...
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 Spring '08
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