This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: choi (hc5878) hw1 Demkov (59910) 1 This printout should have 51 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points A human hair is approximately 53 m in di ameter. Express this diameter in meters. Correct answer: 5 . 3 10 5 m. Explanation: Basic Concept: 1 m = 1 10 6 m Let: diameter = 53 m Solution: diameter = 53 m = ( 5 . 3 10 1 m ) 1 10 6 m 1 m = 5 . 3 10 5 m keywords: /* If you use any of these, fix the comment symbols. 002 (part 1 of 3) 10.0 points A hydrogen atom has a diameter of about 9 . 54 nm. a) Express this diameter in meters. Correct answer: 9 . 54 10 9 m. Explanation: Basic Concept: 1 nm = 1 10 9 m 1 m = 1 10 6 m 1 mm = 1 10 3 m Let: diameter = 9 . 54 nm Solution: diameter = 9 . 54 nm = ( . 954 10 1 nm ) 1 10 9 m 1 nm = 0 . 954 10 8 m 003 (part 2 of 3) 10.0 points b) Express this diameter in millimeters. Correct answer: 9 . 54 10 6 mm. Explanation: Solution: diameter = ( . 954 10 8 m ) 1 mm 1 10 3 m = 0 . 954 10 5 mm 004 (part 3 of 3) 10.0 points c) Express this diameter in micrometers. Correct answer: 0 . 00954 m. Explanation: Solution: diameter = ( . 954 10 8 m ) 1 m 1 10 6 m = 0 . 954 10 2 m keywords: 005 10.0 points A typical radio wave has a period of 1 . 2 s. Express this period in seconds. Correct answer: 1 . 2 10 6 s. Explanation: Basic Concept: 1 s = 1 10 6 s Let: period = 1 . 2 s Solution: period = (1 . 2 s) 1 10 6 s 1 s = 1 . 2 10 6 s keywords: /* If you use any of these, fix the comment symbols. choi (hc5878) hw1 Demkov (59910) 2 006 10.0 points The standard of time is based on 1. the frequency of light emitted by 86 Kr. 2. a precision pendulum clock. 3. the yearly revolution of the earth about the sun. 4. None of these correct 5. the daily rotation of the earth. Explanation: The second is defined from oscillations of cesium133 atoms. 007 10.0 points You can obtain a rough estimate of the size of a molecule by the following simple exper iment. Let a droplet of oil spread out on a smooth water surface. The resulting oil slick will be approximately one molecule thick. Given an oil droplet of mass of 8 . 25 10 7 kg and density of 912 kg / m 3 that spreads out into a circle of radius 44 . 3 cm on the water surface, estimate of magnitude of the diameter of an oil molecule. Correct answer: 1 . 46923 10 9 m. Explanation: Given : m = 8 . 25 10 7 kg , = 912 kg / m 3 , and r = 44 . 27 cm 1 m 100 cm = 0 . 4427 m ....
View
Full Document
 Spring '07
 Swinney
 mechanics, Velocity, Correct Answer, Orders of magnitude

Click to edit the document details