CH301 - heatingcurve3

CH301 - heatingcurve3 - I q = Cs m T ice II q = H m fusion...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
q = C s · m · T q = H · m ice water steam fusion vap 2.09 J/g˙C 4.184 J/g˙C 2.03 J/g˙C 334 J/g 2260 J/g I II III IV V HEAT added bp = 100˚C mp = 0˚C ice and water mixture water and steam mixture ice steam (equilibrium) (equilibrium) q = C s · m · T q = C s · m · T q = H · m water Here you are heating ice up to its melting point of 0˚C. Here you are melting ice into water at its melting point of 0˚C. Here you are heating water up to its boiling point of 100˚C. Here you are boiling water into steam at its boiling point of 100˚C. Here you are heating steam up to whatever temperature you want. temperature Something Different is Happening in Each of the 5 Zones Each of the 5 zones shown above have their own unique formulas for calculating heats. Note that zones I, III, and V are all zones where you have only one phase present and the temperature is changing. The slopes of the curve are NOT zero in these 3 zones. As a matter of fact, the slopes of the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/02/2008 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.

Ask a homework question - tutors are online