CH301 - icewatersteam

CH301 - icewatersteam - The Ice Water and Steam Problem 100...

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HEAT added temperature ice steam water 100 g 100 g 12 g Pull all components to 0˚C. The water is already at 0˚C. The ice just needs to be melted. The steam must be cooled, condensed, and then cooled again. 2.03 J/g˚C · 12 g · 10˚C = 243.6 J 2260 J/g · 12 g = 27120.0 J 4.184 J/g˚C · 12 g · 100˚C = 5020.8 J 32384.4 J 334 J/g · 100 g = 33400.0 J 33400.0 J difference = 1015.6 J q = H · m m = q/ H m = 1015.6 / 334 m = 3.0 grams of ice solve for m COLD SIDE HOT SIDE cold side wins! This heat is equivalent to the mass of ice that did NOT get melted by the
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This note was uploaded on 11/02/2008 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.

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