{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

solutions hw 1

# solutions hw 1 - obennoskey(blo242 – hw1 – Demkov...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: obennoskey (blo242) – hw1 – Demkov – (59910) 1 This print-out should have 51 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A human hair is approximately 46 μ m in di- ameter. Express this diameter in meters. Correct answer: 4 . 6 × 10 − 5 m. Explanation: Basic Concept: 1 μ m = 1 × 10 − 6 m Let: diameter = 46 μ m Solution: diameter = 46 μ m = ( 4 . 6 × 10 1 μ m ) · 1 × 10 − 6 m 1 μ m = 4 . 6 × 10 − 5 m keywords: /* If you use any of these, fix the comment symbols. 002 (part 1 of 3) 10.0 points A hydrogen atom has a diameter of about 9 . 87 nm. a) Express this diameter in meters. Correct answer: 9 . 87 × 10 − 9 m. Explanation: Basic Concept: 1 nm = 1 × 10 − 9 m 1 μ m = 1 × 10 − 6 m 1 mm = 1 × 10 − 3 m Let: diameter = 9 . 87 nm Solution: diameter = 9 . 87 nm = ( . 987 × 10 1 nm ) · 1 × 10 − 9 m 1 nm = 0 . 987 × 10 − 8 m 003 (part 2 of 3) 10.0 points b) Express this diameter in millimeters. Correct answer: 9 . 87 × 10 − 6 mm. Explanation: Solution: diameter = ( . 987 × 10 − 8 m ) · 1 mm 1 × 10 − 3 m = 0 . 987 × 10 − 5 mm 004 (part 3 of 3) 10.0 points c) Express this diameter in micrometers. Correct answer: 0 . 00987 μ m. Explanation: Solution: diameter = ( . 987 × 10 − 8 m ) · 1 μ m 1 × 10 − 6 m = 0 . 987 × 10 − 2 μ m keywords: 005 10.0 points A typical radio wave has a period of 1 . 2 μ s. Express this period in seconds. Correct answer: 1 . 2 × 10 − 6 s. Explanation: Basic Concept: 1 μ s = 1 × 10 − 6 s Let: period = 1 . 2 μ s Solution: period = (1 . 2 μ s) · 1 × 10 − 6 s 1 μ s = 1 . 2 × 10 − 6 s keywords: /* If you use any of these, fix the comment symbols. obennoskey (blo242) – hw1 – Demkov – (59910) 2 006 10.0 points The standard of time is based on 1. the yearly revolution of the earth about the sun. 2. the frequency of light emitted by 86 Kr. 3. the daily rotation of the earth. 4. a precision pendulum clock. 5. None of these correct Explanation: The second is defined from oscillations of cesium-133 atoms. 007 10.0 points You can obtain a rough estimate of the size of a molecule by the following simple exper- iment. Let a droplet of oil spread out on a smooth water surface. The resulting oil slick will be approximately one molecule thick. Given an oil droplet of mass of 8 . 82 × 10 − 7 kg and density of 936 kg / m 3 that spreads out into a circle of radius 42 . 1 cm on the water surface, estimate of magnitude of the diameter of an oil molecule. Correct answer: 1 . 6915 × 10 − 9 m. Explanation: Given : m = 8 . 82 × 10 − 7 kg , ρ = 936 kg / m 3 , and r = 42 . 11 cm · 1 m 100 cm = 0 . 4211 m ....
View Full Document

{[ snackBarMessage ]}

### Page1 / 15

solutions hw 1 - obennoskey(blo242 – hw1 – Demkov...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online