semisolex04

semisolex04 - Semiconductor Physics and Devices Basic...

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Semiconductor Physics and Devices: Basic Principles, 3 rd edition Chapter 4 Solutions Manual Exercise Solutions 35 Chapter 4 Exercise Solutions E4.1 nx o = F H I K 2.8 10 022 00259 19 exp . . or c m o = 573 10 15 3 . Now EE e V Fv −= = 112 090 .. . So px o = F H I K 104 10 19 .e x p . . or c m o = 843 10 33 . E4.2 o = F H I K 7.0 10 030 18 exp . . or c m o = 653 10 13 3 . Now e V cF = 142 030 ... So o = F H I K 4.7 10 17 exp . . or nc m o = 00779 3 . E4.3 (a) For 200 K : kT == () F H I K 200 300 0 01727 Now x i 21 9 1 9 3 2.8 10 200 300 0 01727 = F H I K F H I K b gb g x p . . or i 29 590 10 = . Then c m i = 7.68 10 43 (b) For 400 K : kT F H I K 400 300 0 03453 Now x i 9 1 9 3 2.8 10 400 300 0 03453 = F H I K F H I K b gb g x p . . or i 22 4 565 10 = Then c m i = 2.38 10 12 3 E4.4 (a) 200 K x i 7 1 8 3 4.7 10 7 10 200 300 142 0 01727 = F H I K F H I K bg b g exp . . or n i 2 1904 = Then m i = 138 3 . (b) 400 K x i 7 1 8 3 4.7 10 7 10 400 300 0 03453 = F H I K F H I K b g exp . . or i 9 108 10 = Then c m i = 328 10 93 . E4.5 (a) 200 K x i 9 1 8 3 6 10 200 300 066 0 01727 = F H I K F H I K x p . . b gb g or i 0 4.67 10 = Then c m i = 2.16 10 10 3 (b) 400 K x i 9 1 8 3 400 300 0 03453 = F H I K F H I K x p .

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This note was uploaded on 11/06/2008 for the course ECE 103 taught by Professor Wang during the Fall '08 term at UCSD.

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semisolex04 - Semiconductor Physics and Devices Basic...

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