{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

FerricOxalate - Experiment 7 Revision 1.0 Synthesis of...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Experiment 7 Revision 1.0 Synthesis of Potassium Ferric Oxalate Trihydrate To learn about Coordination Compounds. To learn about metal ion - ligand complexes. To learn about chemical stoichiometry and the Theoretical Yield of a Reaction. To learn about Hydrates. In this Laboratory exercise we will synthesize the Coordination Compound Potassium Ferric Oxalate Trihydrate, K 3 [Fe(C 2 O 4 ) 3 ] 3H 2 O. This compound is the Potassium salt (K + ) of the Trioxalatoferrate(III) complex ion, Fe(C 2 O 4 ) 3 3- . This Complex is itself a result of the bonding between the Ferric Ion (Fe 3+ ) and three Oxalate (C 2 O 4 2- ) ligands. And, in its crystalline form, the compound solidifies with three associate Water molecules as a Hydrate. Coordination Compounds are substances that contain a Complex Ion , a species consisting of a central metal atom, a transition metal or Main Group metal, bound to several ligands . An example is Hexaammine Cobalt (III) Chloride, [Co(NH 3 ) 6 ]Cl 3 , which contains the complex ion Co(NH 3 ) 6 3+ . This salt, just like simpler salts (e.g., NaCl, CaF 2 , etc.) involves Ionic Bonding between the complex ion and the three chloride, Cl - , ions. Further, like many simpler salts, it is soluble in water: [Co(NH 3 ) 6 ]Cl 3 (s) Co(NH 3 ) 6 3+ (aq) + 3 Cl - (aq) In this example, the complex ion contains the Co 3+ transition metal ion and six NH 3 ligands. Each ligand forms a single bond to the central metal ion, resulting in an octahedrally bound complex: The number of bonds formed between the metal center of the Complex and its ligands is referred to as the Coordination Number. In the above example, the Coordination Number is six. The coordination number determines the geometry of these complexes. Typical geometries are:
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Coordination Number Geometry 2 Linear 4 Square Planar or Tetrahedral 6 Octahedral In this case the NH 3 ligand is monodentate, meaning that it forms a single bond with the metal ion. Ligands can be multidentate, forming multiple bonds to the metal center. The Oxalate Ion (C 2 O 4 2- ) is an example of a bidentate ligand; having two bonding points for the metal ion: In this laboratory we will synthesize, in two steps, the Coordination Compound Potassium Ferric Oxalate Trihydrate; K 3 [Fe(C 2 O 4 ) 3 ] 3H 2 O, a salt which contains the Trioxalatoferrate(III) complex ion, Fe(C 2 O 4 ) 3 3- . In this complex, the 3 Oxalate ions, C 2 O 4 2- , form 6 bonds to the Fe 3+ center. This gives the complex an octahedral shape, much like that pictured above for Co(NH 3 ) 6 3+ . The first reaction is the conversion of Ferrous Ammonium Sulfate Hexahydrate, a pale green crystalline solid, to Ferrous Oxalate Dihydrate, a yellow solid: Fe(NH 4 ) 2 (SO 4 ) 2 6H 2 O (s) + H 2 C 2 O 4 (aq) (Ferrous Ammonium (Oxalic Acid) Sulfate Hexahydrate) FeC 2 O 4 2H 2 O (s) + (NH 4 ) 2 SO 4 (aq) + H 2 SO 4 (aq) + 4H 2 O (Ferrous Oxalate (Ammonium Sulfate) Dihydrate) The main product of the first reaction, Ferrous Oxalate Dihydrate, will be separated from the other reaction products, which will remain in solution.
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern