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Chapter 09

# Chapter 09 - CHAPTER 9 Solutions for Exercises E9.1 The...

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CHAPTER 9 Solutions for Exercises E9.1 The equivalent circuit for the sensor and the input resistance of the amplifier is shown in Figure 9.2 in the book. Thus the input voltage is in sensor in sensor in R R R v v + = We want the input voltage with an internal sensor resistance of 10 k to Ω be at least 0.995 times the input voltage with an internal sensor resistance of 5 k . Thus with resistances in k Ω , we have in in sensor in in sensor R R v R R v + + 5 995 . 0 10 Solving, we determine that R in is required to be greater than 990 k . Ω E9.2 (a) A very precise instrument can be very inaccurate because precision implies that the measurements are repeatable, however they could have large bias errors. (b) A very accurate instrument cannot be very imprecise. If repeated measurements vary a great deal under apparently identical conditions, some of the measurements must have large errors and therefore are inaccurate. E9.3 V 2 . 0 5 . 5 7 . 5 2 1 = - = - = v v v d V 6 . 5 ) 7 . 5 5 . 5 ( ) ( 2 1 2 1 2 1 = + = + = v v v cm E9.4 The range of input voltages is from -5 V to +5 V or 10 V in all. We have 256 2 2 8 = = = k N zones. Thus the width of each zone is 1 . 39 10 = = N mV.

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Chapter 09 - CHAPTER 9 Solutions for Exercises E9.1 The...

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