{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

This preview shows pages 1–2. Sign up to view the full content.

Answers to the Homework Problems Chapter 3 Prob. 3.1: (a) N ph = 2.16×10 30 photons per second; (b) Γ ph = 4.02×10 21 photons m -2 s -1 ; (c) E = 868 V m -1 . Prob. 3.3: Φ υ (650 nm) = 0.35 lm; Φ υ (532 nm) = 1.09 lm; Φ 650nm = 1.63×10 16 photons s -1 ; Φ 532nm = 5.35×10 15 photons s -1 . Prob. 3.4: (a) E ph (rod) = 3.92×10 -19 J or 2.45 eV; E ph (cones) =3.58×10 -19 J or 2.24 eV; (b) Φ = 900 photons s -1 ; E total = 3.53×10 -17 J or 221 eV; P = 3.53×10 -16 W; (c) I th = 1.41×10 -7 J s -1 m -2 or 1.41×10 -7 W m -2 ; Total # of rods in test spot = 375 rods; (d) P st = 7.17×10 -15 J s -1 or 7.17×10 -15 W. Prob. 3.5: E ph = 9.945×10 -15 J or 62.15 keV; Φ = 1×10 7 photons cm -2 . Prob. 3.7: (a) Φ = 4.733×10 -19 J or 2.96 eV; (b) KE = 1.18 eV; (c) J = 48.4 A m -2 = 4.84 mA cm -2 . Prob. 3.8: (a) λ max = 653.9×10 -7 m = 653.9 nm; (b) E ph = 4.417×10 -19 J = 2.76 eV; KE = 0.86 eV; The stopping voltage for this wavelength will be -0.86 V; (c) I = 7.691×10 -4 A = 0.769 mA. Prob. 3.9: (a) J = 2.54×10 -3 A cm -2 ; KE = 1.36 eV; (b) The voltage to extinguish the current is -1.36 V; (c) I = 0.105 J s -1 cm -2 or 0.105 W cm -2 . Prob. 3.14: ∆λ = 9.20×10 -15 m or 9.20 fm; l = 6.0 m. Chapter 1 Prob. 1.19: (a) n A = 6.34×10 -9 m -3 ; (b) n A = 1.61×10 16 m -3 . (If using the method of numerical integration, (a) n A = 6.16×10 -8 m -3 ; (b) n A = 8.21×10 16 m -3 .) Prob. 1.22: (a) a = 3.147×10 -10 m = 0.3147 nm; n at = 6.415×10 22

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern