PHYS272 Fall 2008 Exam 1 (Ch21-22) Solutions

PHYS272 Fall 2008 Exam 1 (Ch21-22) Solutions - September...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: September 26, 2007 Physics 272 Exam 1: Name: ' The value of the electric constant eo=8.85 X 10’12 CZ/Nm2 Solve the four problems in the exam. 1.- l+20 nm+| Q Q (D o® 9‘ C9 Q .L—iIEf; rl‘hree charges, each of Q = 3.2 x 10"19 C, are arranged at three of the corners of a 20-nm square as shown. Find the magnitude of the electric field at D, the fourth corner of the square. 4 .—. z 7. I 2 “A1 I J); (HT—Ct» (V740) (H73 :20 (sol 20 (lo {Zuo‘ A ’_ + \ I: ‘ 2L1 ; i #3: -fl' ‘ 75 (3944,». w WWWZZA “4’”? (A >14“ #54” W/flw/fi (MCI/A A C: : / 1.“ ‘7; + l g2 * _f_ 9% A, V/Téagqfll/E‘N): V2 202 V?— 30 .141 /Cp/‘ g / (1-4 I’—)__3,2wo/7 x_L_,i.(’:_—‘ yfl—(l) 202 1 35_y/0”,Z@0VID A conducting sphere has a net charge of -q and of mass m is suspended from the ceiling by a light string. A uniform electric field E is applied vertical down on the sphere. If m = 1 g, q = 1 HC and E = 5000 N/C, Find the tension T in the string. E ."T T+F6—w=0 T: W‘Fc _ 3 4 - _ Y/ox ’0 m/ - gxw 5 \ ~3 ~_— jX/DB‘SXID —3 3.- A solid spherical conductor has a radius of 15 cm. The electric field 30 cm from the center of this sphere has a magnitude of 800 N/C. a) What is the magnitude of the electric field 1 m from the center of the sphere? b) What is the surface charge density 0 on the sphere? I‘é ° 9 A B [<- 43 3w“">l H—M—x 5‘: 800 (.3)‘)‘ a _._. H.800.¢g~],o°3x/0 C/m % (.032 O.) 2_ E. Qfitu) =1. 0126(6) c“ ” °_l__6—[|5)z— ixfr331‘5’oo ,, 4. A long, thin, nonconducting plastic rod is bent into a loop with radius R. Between the ends of the rod, a small gap of length l (K <R) remains. A charge Q is equally distributed on the rod. ‘ a) Indicate the direction of the electric field at the center of the loop. b) Find the magnitude of the electric field at the center of the loop. 0) Find the magnitude of the electric field at the gap of the loop. L3 (Q 4) @a’mmflf i I ' 5) QM; O + £3- It 04 /9 (fia’SféuXaay, 045%! 177%: (my, .' 5277/ng : L A=£ ...
View Full Document

Page1 / 4

PHYS272 Fall 2008 Exam 1 (Ch21-22) Solutions - September...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online