PHYS272 Fall 2008 Exam 1 (Ch21-22) Solutions

# PHYS272 Fall 2008 Exam 1 (Ch21-22) Solutions - Physics 272...

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Unformatted text preview: September 26, 2007 Physics 272 Exam 1: Name: ' The value of the electric constant eo=8.85 X 10’12 CZ/Nm2 Solve the four problems in the exam. 1.- l+20 nm+| Q Q (D o® 9‘ C9 Q .L—iIEf; rl‘hree charges, each of Q = 3.2 x 10"19 C, are arranged at three of the corners of a 20-nm square as shown. Find the magnitude of the electric ﬁeld at D, the fourth corner of the square. 4 .—. z 7. I 2 “A1 I J); (HT—Ct» (V740) (H73 :20 (sol 20 (lo {Zuo‘ A ’_ + \ I: ‘ 2L1 ; i #3: -ﬂ' ‘ 75 (3944,». w WWWZZA “4’”? (A >14“ #54” W/ﬂw/ﬁ (MCI/A A C: : / 1.“ ‘7; + l g2 * _f_ 9% A, V/Téagqﬂl/E‘N): V2 202 V?— 30 .141 /Cp/‘ g / (1-4 I’—)__3,2wo/7 x_L_,i.(’:_—‘ yﬂ—(l) 202 1 35_y/0”,[email protected] A conducting sphere has a net charge of -q and of mass m is suspended from the ceiling by a light string. A uniform electric ﬁeld E is applied vertical down on the sphere. If m = 1 g, q = 1 HC and E = 5000 N/C, Find the tension T in the string. E ."T T+F6—w=0 T: W‘Fc _ 3 4 - _ Y/ox ’0 m/ - gxw 5 \ ~3 ~_— jX/DB‘SXID —3 3.- A solid spherical conductor has a radius of 15 cm. The electric ﬁeld 30 cm from the center of this sphere has a magnitude of 800 N/C. a) What is the magnitude of the electric ﬁeld 1 m from the center of the sphere? b) What is the surface charge density 0 on the sphere? I‘é ° 9 A B [<- 43 3w“">l H—M—x 5‘: 800 (.3)‘)‘ a _._. H.800.¢g~],o°3x/0 C/m % (.032 O.) 2_ E. Qﬁtu) =1. 0126(6) c“ ” °_l__6—[|5)z— ixfr331‘5’oo ,, 4. A long, thin, nonconducting plastic rod is bent into a loop with radius R. Between the ends of the rod, a small gap of length l (K <R) remains. A charge Q is equally distributed on the rod. ‘ a) Indicate the direction of the electric ﬁeld at the center of the loop. b) Find the magnitude of the electric ﬁeld at the center of the loop. 0) Find the magnitude of the electric ﬁeld at the gap of the loop. L3 (Q 4) @a’mmﬂf i I ' 5) QM; O + £3- It 04 /9 (ﬁa’SféuXaay, 045%! 177%: (my, .' 5277/ng : L A=£ ...
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