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Unformatted text preview: Homework 10 November 30, 2007 Problem 1. a)a 1 level con dence interval is ( X z 2 n , X + z 2 n ) . Thus z 2 = 2 . 81 1 2 = 0 . 9854 1 = 0 . 9702 b) z 2 = 1 . 44 1 2 = 0 . 9265 1 = 0 . 8530 c) 1 = . 997 1 2 = 0 . 9985 z 2 = 2 . 97 d)The length l of a con dence interval is 2 z 2 n . z 2 = 1 . 96 n = ( 3 . 92 l ) 2 l = 1 n = (3 . 92 ) 2 ,l = 1 / 2 n = (7 . 84 ) 2 ,l = 1 n = (1 . 96 ) 2 e) n = (2 z 2 ) 2 . 1 = . 9 n = (3 . 3 ) 2 , 1 = . 99 n = (5 . 16 ) 2 , 1 = . 999 n = (6 . 54 ) 2 Problem 2. a) EY=950 b)Y is binomial with P = 0 . 95 ,n = 1000 c) P (940 Y 960) = P ( Y 960) P ( Y 939) = . 9402 . 0671 = 0 . 8731 Problem 3. (a) Note that n ( X n ) / N (0 , 1) , so LHS = ( z 2 ) ( z 1 ) = 1 2 1 = 1 , where is the distribution function of a standard normal....
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This note was uploaded on 11/12/2008 for the course ORIE 360 taught by Professor Ehrlichman during the Fall '07 term at Cornell University (Engineering School).
 Fall '07
 EHRLICHMAN

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