CHEM Module #3 homework (2)

CHEM Module #3 homework (2) - Module 3 EOC Assignment –...

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Module 3 EOC Assignment – Part2 Due by 3/3 Chapter 16 - 15, 23, 25, 27, 29 Chpt16 #15 (1) Provide ALL of the given information. Include constants, density, conversion factors, etc. I 2 (g) 2 I(g) = 3.76 x 10 ³ at 1000K 0.105 mol of I 2 placed in a 12.3-L flask at 1000K (1) State the goal of the problem. What are the concentrations of I 2 and I when the system comes to equilibrium (1) List possible equations that may be used (4) Solve the problem and explain the reason for each step of multiplication, division, addition, or subtraction. 2 mol of I form for each mol of I 2 that reacts, so then it’s 2I and I 2 at equilibrium would be 8.54 a 10 -3 – x. (2I) 2 / 8.54 x 10 -3 = 4I 2 + 3.76 x 10 -3 (8.54 x 10 -3 -x) this needs to be changed to be able to use the quadratic equation and I will change the “I” into an x: 4x 2 + 3.76 x 10 -3 x – 3.21 x 10 -5 = 0 ; which = 2.40 x 10 -3 At equilibrium = I 2 = 8.54 x 10 -3 – 2.40 x 10 -3 = 6.14 x 10 -3 I = 2(2.40 x 10 -3 ) = 4.79 x 10 -3 (1) Explain why your answer makes physical and mathematical sense.
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CHEM Module #3 homework (2) - Module 3 EOC Assignment –...

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