{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW2903_1_sol

# HW2903_1_sol - 1a Convert 245.357d to binary Show 10 digits...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1a) Convert 245.357d to binary. Show 10 digits for the integer portion and 4 bits for the frational portion. 1b) What is the absolute error and the percent error? 1,) M .W 5 A) 3.3.5,:1141 2:”: .unz:,7w/ 0 a”, IT—A/ 9’ , . [I — l . ,3}: 5/ £0 2) = MI ‘77” ’ “’1 5’- 4/ :fuLJI7-w'.m[ 2. I .Lﬂam [Illa/o] éqlgxl {356 00 ’0 . élz‘ 7” A ’ ‘ "Iran :I.~7ll ' I 2 33:15“ ,7!1>,§-»Wuf I. LEVI" amino/01,0I/o1 2) Convert 2AD.ECh to decimal. (IX/‘1)ﬂ-IOH‘P ’3 '*' (Hr/e") ﬂux/g“) : .: I' -- T 1,00: 0. 0 I .7 - ,, x100 7: l‘ffrJJ'7 ’3'!” 3) Convert 59610 to hexadecimafd ~.>;.616_.-3-7£q I .32: IRS- 14. 2: 3 0x1 H; 4) Convert 10011010012 to hexadecimal, assuming that it is a sign magnitude number. {acorn/taliool -/> 3‘67“; 5) Convert the sign magnitude number, 1101101100012, to its 2S complement equivalent. ( alone/mag! L4Mk) ItiecIOc 1"," 4/ 6) A =110101110b, B = 01011110b a) If A and B are unsigned integers, calculate A — B. . ' .. H; 7“. / [It / 9'30 IIUIOIl/o l’qu-lllc' ' ' - -o't-‘rolr'tl'o _: [1010000] _: ~ + I p 336“. 334“, y'lcrwpoéoo b) If A and B are 25 complement integers, calculate A + B. I l/ I / f / .' -9L IHOIOHIO If cw . .. . 4.0.4.0. I.o..t..I..I.La - )VDoca 0 clip a [lie c) If A and B are unsigned integers, calculate A x B. K ....r_...,-u_ .. ........._......';.-_ . e ,1. . . . . . . IUD/I101 Hm 0100l 7) Problem 2.38 from the text. 1 L) Sada/009000114"; Lt 40/0670 9.30 x 4‘} 90410 I0 ...
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

HW2903_1_sol - 1a Convert 245.357d to binary Show 10 digits...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online