CIVL 151_Tutotial 2

CIVL 151_Tutotial 2 - CIVL151Fluidmechanics Tutorial2...

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CIVL 151 Fluid mechanics torial 2 Tutorial 2 17, March, 2009
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Problem 1 Water is flowing in a channel, as shown in the figure. Neglecting all losses, determine the two possible depths of flow y 1 and y 2 .
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Problem 1 1. The control volume is easily established; 2. Position the datum at the bottom of the outlet; 3. Without losses or shaft work, the energy equation is applied: 22 11 2 p Vp V zz + += + + 4. Piezometric head at the two boundaries: 12 gg γ 1 2 ft p = 2 t p y = 5. Kinetic energy: 1 12 ft z . 1 16 1 ft/sec V = 2 ft zy + V 2 is calculated based on continuity at the two boundaries: herefore 41 0 1 0 QV V y = ×× = / 4 4 ft/sec y Therefore, 6. Substitute these into the energy equation, using . 2 64 4 Vy = .. 2 16 1 64 4 2 y 16 028 64 452 0 y + + . 2 32 174 ft/s g = 32 2 12 yy y + = +⇒ = 216 ft and 15 77 ft = =
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Problem 2 Neglecting losses, find the discharge through the Venturi meter.
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Problem 2 1. The control volume is established within the two boundaries of the Venturi meter, i.e., section 1 and section 2; 2. Position the datum at the piezometric head at section 2; 3. Without losses or shaft work, the
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CIVL 151_Tutotial 2 - CIVL151Fluidmechanics Tutorial2...

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