{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

CIVL 151_Tutotial 2

CIVL 151_Tutotial 2 - Tutorial2 Tutorial 2 17,March,2009...

This preview shows pages 1–6. Sign up to view the full content.

CIVL 151 Fluid mechanics torial 2 Tutorial 2 17, March, 2009

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 1 Water is flowing in a channel, as shown in the figure. Neglecting all losses, determine the two possible depths of flow y 1 and y 2 .
Problem 1 1. The control volume is easily established; 2. Position the datum at the bottom of the outlet; 3. Without losses or shaft work, the energy equation is applied: 22 11 2 p Vp V zz + += + + 4. Piezometric head at the two boundaries: 12 gg γ 1 2 ft p = 2 t p y = 5. Kinetic energy: 1 12 ft z . 1 16 1 ft/sec V = 2 ft zy + V 2 is calculated based on continuity at the two boundaries: herefore 41 0 1 0 QV V y = ×× = / 4 4 ft/sec y Therefore, 6. Substitute these into the energy equation, using . 2 64 4 Vy = .. 2 16 1 64 4 2 y 16 028 64 452 0 y + + . 2 32 174 ft/s g = 32 2 12 yy y + = +⇒ = 216 ft and 15 77 ft = =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 2 Neglecting losses, find the discharge through the Venturi meter.
Problem 2 1. The control volume is established within the two boundaries of the Venturi meter, i.e., section 1 and section 2; 2. Position the datum at the piezometric head at section 2; 3. Without losses or shaft work, the

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 10

CIVL 151_Tutotial 2 - Tutorial2 Tutorial 2 17,March,2009...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online