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PracticeChap12_2Key

# PracticeChap12_2Key - 1) C(graphite O2CO2Hof=400 H2...

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1) Using the enthalpies of formation below calculate the enthalpies of the following reactions: C(graphite) + O 2    CO 2                              Δ H o f =-400 H 2  +  ½  O 2    H 2 O                                       Δ H o f =-100 C(graphite) + 2 H 2    CH 4                          Δ H o f =-100 C(graphite) +  ½  O 2  + 2H 2    CH 3 OH        Δ H o f =-200 a) CH 4  + 2O 2    CO 2  + 2H 2 CH 4   C(graphite) + 2 H 2                                     Δ H o f =100 C(graphite) + O 2    CO 2                           Δ H o f =-400         2H 2  + O 2    2 H 2 O                                   Δ H o f =-200                                                               Total = -500 b) 2CH 3

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