4.2 - Blackboard Learning System 9:45 PM Your location...

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Unformatted text preview: Blackboard Learning System 3/29/09 9:45 PM Your location: Assessments › View All Submissions › View Attempt View Attempt 2 of 5 Title: Started: Submitted: Time spent: Problem Set 4.2 March 1, 2009 11:58 PM March 2, 2009 12:27 AM 00:29:09 Total score adjusted by 0.0 Maximum possible score: 10 Total score: 7/10 = 70% Done 1. Differentiate. Find f'(x) for f(x) = e4x + x Student Response A. f'(x) = 8xe2x + 1 B. f'(x) = 8xex 2 + 1 C. f'(x) = 8xe + 1 D. f'(x) = 8xe4x 2 + 1 Score: 2. Differentiate. Find f'(x) for f(x) = (ex + 3) 4 Student Response A. f'(x) = 12 x2 e x3 3 2 Feedback 1/1 Feedback + 3) 3 (e x3 B. f'(x) = 4 (3x2 ex 3)3 C. f'(x) = 4 (ex 3 - 3) 3 D. f'(x) = 4 x2 ex 3 - 1 (ex 3 - 3) 3 Score: 3. Graph the exponential function. http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 1 of 8 1/1 Blackboard Learning System 3/29/09 9:45 PM f(x) = ex - 1 Student Response A. Feedback B. http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 2 of 8 Blackboard Learning System 3/29/09 9:45 PM B. C. D. Score: 4. Find the derivative. Find y' for y = ln (9x3 - x2). 1/1 Student Response http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Feedback Page 3 of 8 Blackboard Learning System 3/29/09 9:45 PM A. B. C. D. y' = y' = y' = y' = 1/1 Score: 5. Graph the function. f(x) = -1 - ln x Student Response A. Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 4 of 8 Blackboard Learning System 3/29/09 9:45 PM B. C. D. http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 5 of 8 Blackboard Learning System 3/29/09 9:45 PM D. Score: 6. Find the derivative. f(x) = ln 1/1 Student Response A. Feedback B. C. D. Score: 7. 0/1 Find the derivative. Find f'(x) for f(x) = 6e 5x + 8 ln(8x + 1). Student Response Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 6 of 8 Blackboard Learning System 3/29/09 9:45 PM A. B. C. D. Score: 8. f'(x) = 30e 5x + f'(x) = 30e 5x + f'(x) = 6e 5x + f'(x) = 6e 5x + 0/1 Provide an appropriate response. The percentage P of consumers who accept a new product is given by P(t) = 100(1 - e- 0.20t ), where t is the time in months. How many months will it take for 77% of the consumer to accept the new product? Student Response A. 8 months B. 9 months C. 10 months D. 7 months Score: 9. Find the derivative. y= 0/1 Feedback Student Response A. Feedback B. C. http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 7 of 8 Blackboard Learning System 3/29/09 9:45 PM D. Score: 10. 1/1 Solve the problem. A company's total cost, in millions of dollars, is given by C(t) = 280 - 30e -t where t = time in years. Find the marginal cost when t = 3. Student Response A. 4.48 million dollars per year B. 13.94 million dollars per year C. 1.49 million dollars per year D. 1.65 million dollars per year Score: 1/1 Feedback Done http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 8 of 8 ...
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