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Unformatted text preview: Blackboard Learning System 4/14/09 4:46 PM Your location: Assessments › View All Submissions › View Attempt View Attempt 2 of 2 Title: Started: Submitted: Time spent: Chapter 4 Problem Set March 29, 2009 10:13 PM March 29, 2009 11:47 PM 01:33:43 Total score adjusted by 0.0 Maximum possible score: 100 Total score: 96/100 = 96% Done 1. Find the elasticity of the demand function as a function of p. x = D(p) = Student Response A. B. C. D. Score: 2. E(p) = E(p) = E(p) = E(p) = 4/4 Feedback Find the elasticity of the demand function as a function of p. x = D(p) = Student Response A. E(p) = Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 1 of 13 Blackboard Learning System 4/14/09 4:46 PM B. C. E(p) = E(p) = D. E(p) = 1 Score: 3. Provide an appropriate response. Suppose that $8000 is invested at an interest rate of 5.5% per year, compounded continuously. How long would it take to double the investment? Student Response A. 2 yr B. 12.6 yr C. 13.6 yr D. 11.6 yr Score: 4. Provide an appropriate response. If is invested at 10 years ? compounded continuously, what is the amount in the account after 4/4 Feedback 4/4 Student Response A. B. C. D. $8442.52 Score: 5. Differentiate. Find f'(x) for f(x) = 4/4 Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 2 of 13 Blackboard Learning System 4/14/09 4:46 PM Student Response A. f'(x) = Feedback B. f'(x) = C. f'(x) = D. f'(x) = 4/4 Score: 6. Differentiate. Find f'(x) for f(x) = (ex + 3) 4 Student Response A. f'(x) = 4 (ex 3 - 3) 3 B. f'(x) = 4 x2 ex 3 - 1 (ex 3 - 3) 3 C. f'(x) = 4 (3x2 ex 3)3 D. f'(x) = 12 x2 ex 3 (ex 3 + 3) 3 Score: 7. Find the derivative. Find f'(x) for 4/4 Feedback 3 Student Response A. f'(x) = Feedback B. f'(x) = e3x -2 http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 3 of 13 Blackboard Learning System 4/14/09 4:46 PM C. D. Score: 8. f'(x) = 4/4 Graph the function. f(x) = -1 - ln x Student Response A. Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 4 of 13 Blackboard Learning System 4/14/09 4:46 PM A. B. C. D. http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 5 of 13 Blackboard Learning System 4/14/09 4:46 PM Score: 9. Find the derivative. 4/4 Find f'(x) for f(x) = 6e 5x + 8 ln(8x + 1). Student Response A. B. C. D. Score: 10. Find the derivative. Find f'(x) for f'(x) = 30e 5x + f'(x) = 30e 5x + f'(x) = 6e 5x + f'(x) = 6e 5x + 4/4 Feedback Student Response A. f'(x) = x + 2 ln B. f'(x) = (1 + 2 ln ) Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 6 of 13 Blackboard Learning System 4/14/09 4:46 PM C. D. Score: 11. f'(x) = 4/4 Differentiate. Find f'(t) for f(x) = (5x - 4)(4x 3 - x2 + 1) Student Response A. f'(x) = 80x 3 - 63x 2 + 8x + 5 B. f'(x) = 80x 3 - 21x 2 + 63x + 5 C. f'(x) = 60x 3 + 63x 2 - 21x + 5 D. f'(x) = 20x 3 + 21x 2 - 63x + 5 Score: 12. Differentiate. Let f and g be functions that satisfy: and Find h'(4) for 4/4 Feedback Student Response A. -6 B. 6 C. 5 D. -5 Score: 13. Provide an appropriate response. 4/4 Feedback The market research department of a national food company chose a large city in the Midwest to test-market a new cereal. They found that the weekly demand for the cereal is given approximately by where x is the number of boxes of cereal (in hundreds) sold each week and $p is the price of each box of cereal. If each box of the cereal costs the company $1.15 to produce, how should the cereal be priced in order to maximize the weekly profit? http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 7 of 13 Blackboard Learning System 4/14/09 4:46 PM Student Response A. $7.96 B. $3.50 C. $3.15 D. $11.30 Score: 14. Differentiate. Find f'(t) for f(x) = . 4/4 Feedback Student Response A. B. C. D. - Feedback Score: 15. Differentiate. Find y' for y = 4/4 Student Response A. Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 8 of 13 Blackboard Learning System 4/14/09 4:46 PM B. C. D. Score: 16. Differentiate. Find for y = 4/4 . Student Response A. = Feedback B. = C. = D. = 4/4 Score: 17. Find the derivative. Find: Student Response Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 9 of 13 Blackboard Learning System 4/14/09 4:46 PM A. B. C. 448x 6 D. 8 Score: 18. Find the derivative. Find f'(x) for f(x) = (4x2 + 3x)2. Student Response A. f'(x) = 32x 3 + 36x 2 + 9x B. f'(x) = 64x 3 + 72x 2 + 18x C. f'(x) = 32x 3 + 36x 2 + 18x D. f'(x) = 64x 3 + 36x 2 + 18x Score: 19. Find all values of x for the given function where the tangent line is horizontal. f(x) = 4/4 Feedback 4/4 Student Response A. 0, ± Feedback B. 0 C. D. ± ± http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 10 of 13 Blackboard Learning System 4/14/09 4:46 PM Score: 20. 0/4 Find the equation of the tangent line to the graph of the given function at the given value of x. f(x) = (x 2 + 12) 3/4; x = 2 Student Response A. B. C. D. Score: 21. Provide an appropriate response. Find dy/dx by implicit differentiation. 2xy - y2 = 1 y= y= y= y= x + 11 x x+5 x+5 4/4 Feedback Student Response A. B. C. D. Score: = = = = 4/4 Feedback http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 11 of 13 Blackboard Learning System 4/14/09 4:46 PM 22. Solve the problem. The concentration of a certain drug in the bloodstream t minutes after swallowing a pill containing the drug can be approximated using the equation where C(t) is the concentration in arbitrary units and t is in minutes. Find the rate of change of concentration with respect to time at t = 4 minutes. Student Response A. B. C. D. Score: 23. Provide an appropriate response. Find f'(x) for f(x) = (ln x) 6 units/min units/min units/min units/min 4/4 Feedback Student Response A. B. C. D. 6 ln5 x E. Feedback Score: 4/4 http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 12 of 13 Blackboard Learning System 4/14/09 4:46 PM 24. Find the elasticity of the demand function as a function of p. x = D(p) = Student Response A. B. C. D. Score: 25. Provide an appropriate response. E(p) = E(p) = E(p) = E(p) = 4/4 Feedback A man 6 ft tall walks at a rate of 5 ft/sec away from a lamppost that is 13 ft high. At what rate is the length of his shadow changing when he is 65 ft away from the lamppost ? Student Response A. B. C. D. Score: ft/sec ft/sec ft/sec ft/sec 4/4 Feedback Done http://online.sdccd.edu/webct/urw/lc4130001.tp0/cobaltMainFrame.dowebct Page 13 of 13 ...
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This note was uploaded on 04/21/2009 for the course MATH 121 taught by Professor Hamidy during the Spring '09 term at Miramar College.

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