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Unformatted text preview: k) Glycerol: not drawn towards either wire 4) Current: 34 mA = .034 amps Average voltage: 80 volts V = IR R = V/I R = 80 volts/ .033 amps R = 2352.94 ohms ( ) Ω Average resistance during electrophoresis: 2.353K Ω 5) V initial / R initial = V final / R final V final = (V initial / R initial )R final V final = (60 volts/ R initial ) (2R initial ) V final = 120 volts 6) a) V = 60 volts I = 34 mA P = V x I P = 60 volts x 34mA P =2040 mW b) P=VI and V=IR 2V=I(2R) 2P= (2V)I So if resistance doubles, then voltage doubles; and when voltage doubles, power also doubles. Heat production increases by a factor of 2 during the electrophoresis run if the resistance doubles....
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This note was uploaded on 11/30/2008 for the course BIO 205L taught by Professor Hanson during the Fall '07 term at University of Texas.
- Fall '07