ex7 - Exercise 7 Analysis 1. C1 x V1 = C2 x V2 C1 =...

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Exercise 7 Analysis 1. C 1 x V 1 = C 2 x V 2 C 1 = concentration of protein in the LE 1:20 dilution V 1 = 2µL = .002mL V 2 = 20µL = .02mL C 2 =0.116 mg/mL C 1 (.002mL) = (.116 mg/mL) (.02mL) C 1 = 1.16 mg/mL 2. C 1 x V 1 = C 2 x V 2 C 1 = concentration of protein in the Original Liver Crude Extract V 1 = 50µL = .05mL V 2 = 1000µL = 1mL C 2 =1.16 mg/mL C 1 (.05mL) = (1.16 mg/mL) (1mL) C 1 = 23.2 mg/mL 3. C 1 x V 1 = C 2 x V 2 C 1 = concentration of protein in the Original Tripe Crude Extract V 1 = 10µL = .01mL V 2 = 20µL = .02mL C 2 =0.105 mg/mL C 1 (.01mL) = (0.105 mg/mL) (.02mL) C 1 = 0.21 mg/mL 4. Total protein in the Original Liver Crude Extract = (mg/mL of protein in the Original Liver Crude Extract)(Total volume of Original Liver Crude Extract) Total protein in Original Liver Crude Extract: (23.2 mg/mL)(5mL) Total protein in Original Liver Crude Extract: 116 mg 5. Relative amount Original Liver Crude Extract = (total amount of protein in extract)/ (wet weight of tissue extracted)
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ex7 - Exercise 7 Analysis 1. C1 x V1 = C2 x V2 C1 =...

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