Solution1

Solution1 - EE 200 – Fall 2008(Weber Homework 1 Solutions...

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Unformatted text preview: EE 200 – Fall 2008 (Weber) Homework 1 Solutions 1. The function definition is divided into four parts: y = − x − 2 if − 2 ≤ x ≤ − 1 x if − 1 ≤ x ≤ 1 − x + 2 if 1 ≤ x ≤ 2 otherwise 2. ( f 1 ◦ f 2 )( x ) = 0 . 5 signum (2 sin( πx )) ( f 2 ◦ f 1 )( x ) = 2 sin( π × . 5 signum ( x )) ( f 1 f 2 )(x) 1 1 2-1-2-1 x ( f 2 f 1 )(x) 1 1 2-1-2-1 x-2 2 3. (a) This is a graph of a function. x ∈ X y ∈ Y a 1 b 1 c 2 (b) Not a graph of a function. For a in domain there are two possible values in the range. (c) Not a graph of a function. The value of the function is not given for c in the domain. 4. From the definition of RMS voltage given on page 7 of the text, V RMS = radicalBigg 1 T integraldisplay T ( V Peak sin(2 π 60 t )) 2 dt = V Peak radicalBigg 1 T integraldisplay T sin 2 (2 π 60 t ) dt 1 The thing under the square root works out to 1 T integraldisplay T sin 2 (2 π 60 t ) dt = 1 T integraldisplay T parenleftbigg 1 2 − 1 2 cos(2...
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This note was uploaded on 12/03/2008 for the course EE 200 taught by Professor Zadeh during the Fall '08 term at USC.

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Solution1 - EE 200 – Fall 2008(Weber Homework 1 Solutions...

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