1-11 - (1.00 * 6.41) (1.50 * 8.02) (2.00 * 9.56) (0.000...

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1a. Volume of the mixture (x) fluorescence of the solution (y) 0.000 3.26 0.500 4.80 1.00 6.41 1.50 8.02 2.00 9.56 slope of the line 3.16 concentration of the standard 2.0000 μg/mL
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1b. For every 0.5mL of standard added, the fluorescence increased from 3.26 to 4.80, 4.80 to 6.41, 6.41 to 8.02, and from 8.02 to 9.56. The difference is 1.54, 1.61, 1.61, and 1.54 respectively. When 0mL of standard solution was added, the fluorescence reading was 3.26. So the actual amount of the unknown was: μ = 3.26 2.12 1.54 / g g and = 3.26 2.02 1.61 / g g Since only 5mL of unknown was used for analysis, so the concentration of the unknown is: = 2.12 0.424 / 5.00 g g mL mL and = 2.02 0.404 / 5.00 g g mL mL The average is + = 0.424 0.404 / 0.414 / 2 g mL g mL
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1c. y = mx + b m = 3.16, b = 3.26 so the equation is y = 3.16x + 3.26 = = - + 2 1 [ ( )] N resid i i i SS y b mx + + + + = = + + + + = = (3.26 4.80 6.41 8.02 9.56) 6.41 5 (0.000 0.500 1.00 1.50 2.00) 1 5 y x = - = - + - + - + - + - 2 2 2 2 2 2 ( ) (0.000 1) (0.500 1) (1.00 1) (1.50 1) (2.00 1) xx i S x x = 2.50 = - 2 ( ) yy i S y y = - + - + - + - + - 2 2 2 2 2 (3.26 6.41) (4.80 6.41) (6.41 6.41) (8.02 6.41) (9.56 6.41) = 25.1 = - - = - ( )( ) i i xy i i i i x y s x x y y x y N = + + + + + + + + + + + + - (0.000 * 3.26) (0.500 * 4.80)
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Unformatted text preview: (1.00 * 6.41) (1.50 * 8.02) (2.00 * 9.56) (0.000 0.500 1.00 1.50 2.00) * (3.26 4.80 6.41 8.02 9.56) 5 =-= 39.96 32.05 7.91 = = = 7.91 3.16 2.50 xy xx S m S The intercept, b: =-=-= 6.41 3.16 * 1 3.25 b y mx So the equation is: y = 3.16x + 3.25 1d. μ = = * 2 3.25 * 2 0.410 / * 5 3.16 * 5 b g mL m 1e. Standard deviation about regression:--= = =--2 2 25.1 (3.16) * 2.50 0.213 2 5 2 yy xx r S m S S N Standard deviation of the slope: = = = 2 2 0.213 0.135 2.50 r m xx S S S Standard deviation of the y-intercept: =-∑ ∑ ∑ 2 2 2 ( ) i b r i i x S S N x x + + + + = + + + +-+ + + + 2 2 2 2 2 2 2 2 2 2 2 (0.000 0.500 1.00 1.50 2.00 ) 0.213 5(0.000 0.500 1.00 1.50 2.00 ) (0.000 0.500 1.00 1.50 2.00) = = 0.600 * 0.213 0.128 Standard deviation of the result obtained in 1d was: = = 0.128 * 2 0.379 0.135 * 5 b m S S...
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This note was uploaded on 12/12/2008 for the course WHO CARES 23948 taught by Professor Asshole during the Spring '08 term at University of Houston.

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1-11 - (1.00 * 6.41) (1.50 * 8.02) (2.00 * 9.56) (0.000...

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