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egm2511 pe 3

# egm2511 pe 3 - What distance does “x” have to be to...

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The summer before he entered high school, Prof. Schueller’s had to run the farm because his father had an emergency appendectomy. To adjust the “thread” (the width between the wheels) of a John Deere 4020 tractor, a torque of about 1600 ft-lbs. was needed to loosen the rusted clamping bolts. a. How much force must be applied at the end of a 18-inch wrench to loosen the bolts? b. Since that force is too high, Schueller wants to put a piece of pipe on the wrench and stand on the pipe to supply the necessary torque. He weighs 100 lbs. and stands on the pipe at “x” below. (No one stands at x / 2 for this part of this problem.)

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Unformatted text preview: What distance does “x” have to be to loosen the bolts? c. Ed, the local 250-pound all-conference offensive tackle, is a hired hand. If he helps and one person stands at “x” and another at “ x / 2 ”, what is the minimum distance for “x”? d. Assume that “x” = 6 ft. If Ed stands at “x” and Schueller at “ x / 2 ” and they start at a horizontal position, how far ( φ in degrees) will they be able to turn the bolts? [Bonus questions (not to be graded): Would jumping up and down on the pipe help? Did the local Sears store replace the broken Craftsman “lifetime guaranteed” wrench?]...
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egm2511 pe 3 - What distance does “x” have to be to...

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