CourseHeroChemLab4

CourseHeroChemLab4 - Date Performed: 2/15/2008 Date...

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Date Performed: 2/15/2008 Name: removed Date Submitted: 2/22/2008 Partner: removed Instructor: Shengliang Zhao Determination of a Chemical Formula Objective: The objective of this experiment was to determine the percentage composition and simplest formula for an oxide of copper by its reduction with methane gas at approximately 500 °C. Experimental Data: Mass of test tube- 17.581 g +/- 0.0005 g Mass of test tube and copper oxide- 19.599 g +/- 0.0005 g Mass of test tube and copper after reaction- 19.209 g +/- 0.0005 g Sample Calculations: Mass of copper oxide = Mass of test tube and copper oxide – mass of test tube Mass of copper oxide = 19.599 g - 17.581 g = 2.018 g +/- 0.0007 g Mass of copper = Mass of test tube and copper after reaction – mass of test tube = 19.209 g – 17.581 g = 1.629 g Cu +/- 0.0007 g Mass percentage of copper = Mass copper/ mass copper oxide = 1.629 g / 2.018 g *100 % = 80.72 % +/- 0.04 % Mass of oxygen = Mass of copper oxide – mass of copper = 2.018 g – 1.629 g = 0.389 g +/- 0.0007 g
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This note was uploaded on 03/19/2008 for the course CHEM 1045 taught by Professor Pgamateis during the Spring '08 term at Virginia Tech.

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CourseHeroChemLab4 - Date Performed: 2/15/2008 Date...

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