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Lecture 7.pptx

Lecture 7.pptx - Lecture 7 HEAD FORM OF BERNOULLIS...

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HEAD FORM OF BERNOULLI’S EQUATION (P/  + gz + V 2 /2) = dW n,f /dm – F Divide throughout by ‘g’ (P/ g + z + V 2 /2g) = dW n,f /gdm – F /g (P/ g + z + V 2 /2g) = dW n,f /gdm – F /g Head form of B.E. Every term in the above equation has unit of length. Lengths are conceptually converted into ‘ z’, elevation and elevations are referred as ‘Heads’. Pressure head gravity head Velocity head Pump or turbine head Frictional head loss Lecture 7
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1. Diameter of tank is too large, V 1 =0 2. Pressures at points 1 and 2 are local atmospheric pressures, P=0 3. No friction or external work. 4. Flow is steady, level is maintained. (P/  + gz + V 2 /2) = dW n,f /dm – F P=0, dW n,f /dm = 0, V 1 = is practically zero, F can be neglected g(z 2 – z 1 ) + V 2 2 /2 = 0 V 2 = (2gh  TORRICELLI’S EQUATION At point (1), V 1 = 0 (2) (V 2 ) (1) h
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V 2 = (2gh  TORRICELLI’S EQUATION TO FIND OUT VELOCITY At point (1), V 1 = 0 If height of liquid in a tank is 30 ft, what is the velocity of flow out of the nozzle?
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