Lecture 7.pptx - Lecture 7 HEAD FORM OF BERNOULLIS...

Info icon This preview shows pages 1–4. Sign up to view the full content.

HEAD FORM OF BERNOULLI’S EQUATION (P/  + gz + V 2 /2) = dW n,f /dm – F Divide throughout by ‘g’ (P/ g + z + V 2 /2g) = dW n,f /gdm – F /g (P/ g + z + V 2 /2g) = dW n,f /gdm – F /g Head form of B.E. Every term in the above equation has unit of length. Lengths are conceptually converted into ‘ z’, elevation and elevations are referred as ‘Heads’. Pressure head gravity head Velocity head Pump or turbine head Frictional head loss Lecture 7
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

1. Diameter of tank is too large, V 1 =0 2. Pressures at points 1 and 2 are local atmospheric pressures, P=0 3. No friction or external work. 4. Flow is steady, level is maintained. (P/  + gz + V 2 /2) = dW n,f /dm – F P=0, dW n,f /dm = 0, V 1 = is practically zero, F can be neglected g(z 2 – z 1 ) + V 2 2 /2 = 0 V 2 = (2gh  TORRICELLI’S EQUATION At point (1), V 1 = 0 (2) (V 2 ) (1) h
Image of page 2
V 2 = (2gh  TORRICELLI’S EQUATION TO FIND OUT VELOCITY At point (1), V 1 = 0 If height of liquid in a tank is 30 ft, what is the velocity of flow out of the nozzle?
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 4
This is the end of the preview. Sign up to access the rest of the document.
  • Fall '17

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern