Lecture 14.pptx

Lecture 14.pptx - Lecture 14 Fittings Valves Adjusted...

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Lecture 14
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Fittings: Adjusted length = actual pipe length + equivalent length for fittings Resistance coefficient (K) is related through F = K V 2 /2 Equivalent length= L/D Valves: http://www.youtube.com/watch? v=txDANNh4_ME http://www.youtube.com/watch? v=9h4YcBLTJJ8 http://www.youtube.com/watch? v=voXKtQAeRa4 Ball valve Gate valve Safety relief valve
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CLASSROOM EXAMPLE PROBLEM- Water (density 62.3 lbm/ft3, viscosity 50 cP) a rate of 60 gal/min is flowing steadily from tank-A to tank-B through a 3000 ft sch 40 commercial steel pipe 3 inch in diameter. The levels of fluid in both tanks are same. Tank-B is vented to atmosphere. There are two globe valves, ten check valve, four 45 o standard elbow and two couplings installed on a pipeline. Determine gauge pressure in Tank-A and pressure drop associated with valves and fittings (assume density and viscosity of water at ambient conditions). 1 ft 3 = 7.48 gal cP = 6.72.10 -4 lbm/ft.s
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LAMINAR FLOW THROUGH NON-CIRCULAR CHANNEL Q= (P 1 -P 2 ).( .D o 4 )/( x. .128) Circular tube Q= (P 1 -P 2 ).( lh 3 )/( x.
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