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Lesson 3.ppt - Lecture 3 Basic Equation of Fluid Statics...

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Basic Equation of Fluid Statics – Non Vertical Direction dP/dz= - g (barometric equation) dP/da (?) dP/dz= (dP/da).(da/dz)= - g cos ( ) = = dz/da dP/da= - g .(dz/da) = - g cos( ) x y z x y z Bottom Top z=0 (x=0, y=0, z=0) z= z - + a z/ a Lecture 3 Jan 16 2015 1
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Force= Mass . Acceleration lbm lbf lb kgm kgf kg Gravitational acceleration= 9.8 m/s 2 or 980 cm/s 2 or 32.2 ft/s 2 1 lbf = 1 lbm . 32.2 ft/s 2 (1) 1 kgf= 1 kgm. 9.8 m/s 2 (2) Kgf ≠ kgm why? If we divide kgf to both sides in eq (2) lbf ≠ lbm 1 kgf/kgf= 1 kgm/kgf 9.8 m/s 2 and assume kgm=kgf 1=9.8 m/s 2 (absurd) Jan 16 2015 2
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PRESSURE DEPTH RELATIONSHIP P/ z= - g (P 2 – P 1 ) = - g (z 2 -z 1 ) How can we use the above eq to find pressure at some depth? Classroom problem An oil storage tank is 60 ft deep and contains an oil of density 55 lbm/ft3. If top is open to atmosphere. What is the gauge-pressure at the bottom of the tank? http://www.engineeringtoolbox.com/pressure-d_587.html?
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