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Unformatted text preview: This Problem Set has four problems with multiple parts. Each problem is worth 10 points
total. You are required to SHOW ALL YOUR WORK and give complete explanations when appropriate. Don’t hesitate to use words to explain what you are doing along the way. Circle or
highlight the ﬁnal answers in yellow. Be sure to include units where appropriate. It is
recommended that you print the problem set worksheet and work the problems manually.
You may scan the completed worksheet or take a picture of the worksheet. Insert the picture or scan into a Word document for submission. Upload the ﬁnal document to
submit. The four questions below constitute the Lesson 2 Problem Set and will be graded. Answer the questions below: 1. The width and length of a room are 3. 2 yd and 4 0 yd respectively The height of
the roomis  4:3 11290“ \‘wo XKxéés a. What 15 the volume of the room in cubic meters?
\r=\.>keb x\\
5'33. “\ .Cﬁk‘h—T‘V ' s the area 0 i 'e ceiling in the room in square centimeters? «55) PM “£_%W§A cm Doﬁ¢£\\\°\o§50 ”ﬂéchn‘s wa
WY sky0° 0k ‘r
_ ‘3‘. io\ >039
«9% K\.s>~ :33. '3‘ r;
m: “”5 L“ w \m use 05 Cm 2. Vector R has a 35mm at an angle of 30° above the x—axis.
a. Find the x—component of v 0
(1.013030 \sz >(_"' “'5' S733 . ,‘gﬁ’awhﬁ
I) Find the y—component CGBWMW Q6::4\0’=‘{’ ofect v
§\nkm\‘\% (KJJRE. “he, '6\ ﬁ¢=c£___’
UCB‘Ee (VestQ‘— ﬁsh “ﬂak“‘03“
km“ 9"": Eﬂ‘m m\\€» (e: ‘sﬁfske‘Rﬁwks Sm“) \, k. c. If the xcomponent of vector R is doubled and ycomponent remains the ‘3‘ same7 what is ttée resul ' ' de ' ion of the new vector Q7
Q3: :43 ”c Ls}? 3&1) 3:?b\=\‘e.\ Mk2) ) g
wraca‘A‘s: Calij n\—\
X 3%3C¢=§GS ‘ 3. A‘student walks 30 meters east followed by 20 meters north followed by 50
meters west. 21. Use vector arrows to sketch the path that the student followed: (ﬁg 30
s Tmm
64* “—“—> b. What is the total distance traveled by the student?
Odd goer’AO‘tSO: \Qem Smden‘t Romekgé‘ 0&5“:th Q00 kac~§
c. What is the student’s displacement? 66o\o.cemen‘<=\w c33§§zmm ‘oiw Qi’hob‘ gus‘ééiocx GQW
Qﬁbaﬁgﬁé‘ “if equgx $©$\\“xer~ 63% C363L<§r \{kﬁthe
50 ~56 2 QC) W\Ef<‘$ m0<*\\m§\ ESQ 4. V§E§A, E, ahkdbC are deﬁned below: $11.35) Lgbﬁo?{* 5
'5‘ ° > ‘ I ‘_
m, ‘ '1 Q R C) \ «Gab "(5
a“) go A = 30 meters at 0 ° ”5 00 x O 4‘: K 3 CS— LSJQ§$
”5‘2 \ B =10 meters at 270° ”‘0“ 3: J“ ‘5 ’“T O 83: \\O w C =15 meters at 60° .5 gig3* :5 “5—” “3—23 Vector D is the sum of all the vectors such that D = A+B+C. WU \ 
3. W531: ggg‘nﬁtga SECEEO vego>l3§2§ .L . 7
A Comobmnm > ”313%? 5 ®
wamwﬁ‘s .1) —\O*\b:® b. What is the magnitude and direction of vector D? <5 9H3“ 531 ‘* 993% 22 = m«“ L%\
, 25er .. lb.
91 Ame, Cé=’ccx\\ (“ﬁg ...
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 Spring '17
 Almala
 Physics, Work

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