PROBLEM SET 1 .docx - This Problem Set has four problems...

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Unformatted text preview: This Problem Set has four problems with multiple parts. Each problem is worth 10 points total. You are required to SHOW ALL YOUR WORK and give complete explanations when appropriate. Don’t hesitate to use words to explain what you are doing along the way. Circle or highlight the final answers in yellow. Be sure to include units where appropriate. It is recommended that you print the problem set worksheet and work the problems manually. You may scan the completed worksheet or take a picture of the worksheet. Insert the picture or scan into a Word document for submission. Upload the final document to submit. The four questions below constitute the Lesson 2 Problem Set and will be graded. Answer the questions below: 1. The width and length of a room are 3. 2 yd and 4 0 yd respectively The height of the roomis - 4:3 11290“ \‘wo XKxéés a. What 15 the volume of the room in cubic meters? \r=\.->keb x\\ 5'33. “\ .Cfik‘h—T‘V ' s the area 0 i 'e ceiling in the room in square centimeters? «55) PM “£_%W§A cm Dofi¢£\\\°\o§50 ”fléchn‘s wa WY sky-0° 0k ‘r _ ‘3‘. io\ >039 «9% K\.-s>~ :33. '3‘ r; m: “”5 L“ w \m use 05 Cm 2. Vector R has a 35mm at an angle of 30° above the x—axis. a. Find the x—component of v 0 (1.013030 \sz >(_"' “'5' S733 . ,‘gfi’awhfi I) Find the y—component CGBWMW Q6::4\0’=‘{’ ofect v §\nkm\‘\% (KJJRE. “he, '6\ fi¢=c£___’ UCB‘Ee (Vest-Q‘— fish “flak-“‘03“ km“ 9"": Efl‘m m\\€» (e: ‘sfifske-‘Rfiwks- Sm“) \, k. c. If the x-component of vector R is doubled and y-component remains the ‘3‘ same7 what is ttée resul ' ' de ' ion of the new vector Q7 Q3: :43 ”c Ls}? 3&1) 3:?b\=\‘e.\ Mk2) ) g wraca-‘A‘s: Cali-j n\—\ X 3%3C¢=§GS ‘ 3. A‘student walks 30 meters east followed by 20 meters north followed by 50 meters west. 21. Use vector arrows to sketch the path that the student followed: (fig 30 s Tmm 64* “—“—> b. What is the total distance traveled by the student? Odd goer’AO‘tSO: \Qem Smden‘t Romekgé‘ 0&5“:th Q00 kac~§ c. What is the student’s displacement? 66o\o.cemen‘<=\w c33§§zmm ‘oiw Qi’hob‘ gus‘ééiocx GQW Qfibafigfié‘ “if equgx $©$\\“xer~ 63% C363L<§r \{kfithe- 50 ~56 2 QC) W\Ef<‘$ m0<*\\m§\ ESQ 4. V§E§A, E, ahkdbC are defined below: $11.35) Lgbfio?{* 5 '5‘ -° > ‘ I ‘_ m, ‘ '1 Q R C) \ «Gab "(5 a“) go A = 30 meters at 0 ° ”5 00 x O 4‘: K 3 CS— LSJQ§$ ”5‘2 \ B =10 meters at 270° ”‘0“ 3: J“ ‘5 ’“T- O 83: \\O w C =15 meters at 60° .5 gig-3* :5 “5—” “3—23 Vector D is the sum of all the vectors such that D = A+B+C. WU \ - 3. W531: ggg‘nfitga SECEEO vego>l3§2§ .L . 7 A Comobmnm -> ”313%? 5 ® wamwfi‘s .1) —\O*\b:® b. What is the magnitude and direction of vector D? <5 9H3“ 531 ‘* 993% 22 = m«“ L%\ , 25er .. lb. 91 Ame, Cé=’ccx\\ (“fig ...
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