Exam Final Solutions1.pdf - Name 5 15 a...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Name: 515 --> a) In the cirqrit shown, the qJnent source ia of thelarqest cr.rrrent, 6,tu // t? {Z =. 4 {r- tsA Jivl$,ts... 5A ',1 '.1 i, I f$+c I Lor6asF gnrent ; ra = 5A \{L loA l2{t ta o O$rr+*- I \A - 4<r. t 5l-c ---> b) Findthevatueof R sucfrthatthevotbge V*=i}V. . kVL-: t00 -(t)(rOx) -eo = e qro\) t - Ao L = B rnA o $hvn'{, Lq'rrr: 20 = (i)( R 2o = (Bm) Cel R= ffo* t00y G = Z.El K.ru --> L' lokQ l R b + 20v 5la -+ c) Find the vottage v, as shownin the circuitbelow. _ bto + : L'*+ c o 15$L , \(cL -. t$ t1 4 B h.-- o +Q i z. 4,4 'o =+(9 T.or. O E @ tr.l-q- tol -5r-o =o IVL J - 5z- lSto - sio-- o \BCo: ba io= 52- rB k t: '\Jo : ({")(b)
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Name: rD#: 515 -+ d) superposition pdncipb to find thecontrbution ottf" S 5v 2{L so\ = -E -A 9+$ {ot= - 2V 3n + ( Ar^ i _-l + zls -> e) i For the .P.AMP ot*it *rffi VSsVn t o u?= .rrVo ) i,r>: - l-oE t+ = e-dr : fo-- 0.2rnA A tsutnq o3-Nl..q t ), tc l&o.0 2 ofe.robt ," tR" Frorn Connechor,, }sCL noCg qrv'1 , o'\rq = W totl tV = 6-Vo er}- Uo= \t Oin*r rnsdr. 5v 0.lrrrrt 515 ___> 0 Forthe opAMp. cirqritbetow, [email protected] c'g: o 2k, u( = un F.owl co.nneclion ut= o tt! un=o up: s . K gL n"d.e, (mu) : u,(-\lo 1t.- +( ts((-nJ.):o 2cos(3oor)v No =-(uts)C {tr9 dr Ns = (taS1 (ttu)( eOo sir\, Boo L ) No= G gtn\ogb
Image of page 2
Name: tD#: zaf 2a Problem (2) \o/ro-> a)
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern