Lecture 24.pptx - Lecture 24 CBE 218 Fluid Mechanics April...

Info icon This preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Lecture 24 CBE 218 Fluid Mechanics April 1, 2015
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Pump efficiency (ɳ) = useful work/total work= (ΔP/ )/(dWn,f/dm) dWn,f/dm = Δ (P/  + gz + V 2 /2) + F ɳ = ṁ(ΔP/ )/ṁ (dWn,f/dm) ɳ = ṁ(ΔP/ )/(dm/dt) (dWn,f/dm) dWn,f/dt = Power (supplied) Q= ṁ/ ɳ = Q.(ΔP)/POsupplied A pump is pumping 50 gal/min of water from a pressure of 30 psia to a pressure of 100 psia. The changes in elevation and velocity are negligible. The motor that drives the pump supplies 2.8 hp. What is the efficiency of a pump? ɳ = hydraulic horse power/total power supplied. 1 gal = 231 in 3 1 hp = 33,000 ft.lbf/min
Image of page 2
P.D. Pump (constant volumetric flow device) Volumetric flow rate = (piston area* piston travel*cycle)/time
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Problem 10.1 How many gallons per minute should be delivered by a pump with a piston area of 10 in 2 and a piston stroke of 5 in and a speed of 1 Hz? Problem 10.2 Calculate the hydraulic horsepower for pumping 500 gal/min from an inlet pressure of 5 psig to an outlet pressure of 30 psig.
Image of page 4
Centrifugal pump - 1Q
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Centrifugal pump Pump head = h (height to which the pump will lift a fluid at a given flow rate.
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern