{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lecture 24.pptx

Lecture 24.pptx - Lecture 24 CBE 218 Fluid Mechanics April...

Info iconThis preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Lecture 24 CBE 218 Fluid Mechanics April 1, 2015
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Pump efficiency (ɳ) = useful work/total work= (ΔP/ )/(dWn,f/dm) dWn,f/dm = Δ (P/  + gz + V 2 /2) + F ɳ = ṁ(ΔP/ )/ṁ (dWn,f/dm) ɳ = ṁ(ΔP/ )/(dm/dt) (dWn,f/dm) dWn,f/dt = Power (supplied) Q= ṁ/ ɳ = Q.(ΔP)/POsupplied A pump is pumping 50 gal/min of water from a pressure of 30 psia to a pressure of 100 psia. The changes in elevation and velocity are negligible. The motor that drives the pump supplies 2.8 hp. What is the efficiency of a pump? ɳ = hydraulic horse power/total power supplied. 1 gal = 231 in 3 1 hp = 33,000 ft.lbf/min
Background image of page 2
P.D. Pump (constant volumetric flow device) Volumetric flow rate = (piston area* piston travel*cycle)/time
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Problem 10.1 How many gallons per minute should be delivered by a pump with a piston area of 10 in 2 and a piston stroke of 5 in and a speed of 1 Hz? Problem 10.2 Calculate the hydraulic horsepower for pumping 500 gal/min from an inlet pressure of 5 psig to an outlet pressure of 30 psig.
Background image of page 4
Centrifugal pump http://www.youtube.com/watch?v=BaEHVpKc- 1Q
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Centrifugal pump Pump head = h (height to which the pump will lift a fluid at a given flow rate.
Background image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}