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Assignment 11.docx - 4.62 Obtained from SPSS n=12 X =3.03...

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4.62 Obtained from SPSS n = 12 ´ X = 3.03 S = 0.1 a) O bs e rv edV a lu e E xpec tedN o rm a l N o rm a lQ -Q P lo t o fμP e rc en tag e o f E n r ichm en t According to the statistically significance value of the normality test from SPSS, it would be reasonable to model the data using a normal probability distribution as it follows a normal distribution bell curve since significance values are greater than 0.05. b ¿ Parameter : μ percentageof enrichment of fuel rods H 0 : μ = 2.95
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H 1 : μ≠ 2.95 Assume α = 0.01 ¿ part C Test Statistic : T 0 = ´ X μ 0 S n Reject H 0 if P < 0.01 Computation : T 0 = 3.03 2.95 0.1 12 = 2.770.01 ≤P value≤ 0.02 Conclusion: P value ¿ 0.01 : fail to reject null hypothesis and conclude that the μ percentage of enrichment of fuelrods is 2.95 c) CI = ´ X t 0.01 2 , 12 1 ( S n ) ≤ μ≤ ´ X + t 0.01 2 , 12 1 ( S n ) CI = 3.03 3.106 ( 0.1 12 ) ≤μ≤ 3.03 + 3.106 ( 0.1 12 ) = 2.94 ≤ μ≤ 3.12 Since the μ percentage of enrichment of fuelrods of 2.95% falls within the 99% CI, we fail to reject the null hypothesis and conclude that the mean percentage of enrichment is 95%.
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