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HW2_solution_EE163A_2015Fall.pdf

HW2_solution_EE163A_2015Fall.pdf - 4.12 4.18 4.20 2(a = 0 =...

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4.12
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4.18 4.20 (a) 𝑍 ? = 𝑍 0 2 𝑍 𝐿 = 50 𝑜ℎ? 𝑉 ? = 𝑉 𝑠 𝑍 𝐴 𝑍 𝐴 +𝑅 𝑠 = 30 × 50 50+100 𝑉 = 10 𝑉 𝑷 ? = 𝑽 ? ? ?? ? = ? 𝒘?𝒕𝒕 (b) Γ 𝐿 = 𝑍 𝐿 −𝑍 0 𝑍 𝐿 +𝑍 0 At Reference surface B, 𝑉 ? = 𝑉 ? + Γ 𝐿 , 𝑉 ? = 𝑉 ? + + 𝑉 ? = 𝑉 ? + (1 + Γ 𝐿 ) At Reference surface A, 𝑉 ? = 𝑉 ? + + 𝑉 ? = 𝑉 ? 𝑒
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