C301 Exam 4 solutions - 1A 1 H 1.008 3 Li 6.94 11 Na 22.99...

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1A 8A 1 2 H He 1.008 2A 3A 4A 5A 6A 7A 4.003 3 4 5 6 7 8 9 10 Li Be B C N O F Ne 6.94 9.01 10.81 12.01 14.01 16.00 19.00 20.18 11 12 13 14 15 16 17 18 Na Mg Al Si P S Cl Ar 22.99 24.30 3B 4B 5B 6B 7B ———8B——— 1B 2B 26.98 28.09 30.97 32.06 35.45 39.95 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr 39.10 40.08 44.96 47.90 50.94 52.00 54.94 55.85 58.93 58.71 63.55 65.41 69.72 72.64 74.92 78.96 79.90 83.80 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe 85.5 87.6 88.9 91.2 92.9 95.9 98.9 101.1 102.9 106.4 107.9 112.4 114.8 118.7 121.7 127.6 126.9 131.3 55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn 132.9 137.3 138.9 178.5 180.9 183.9 186.2 190.2 192.2 195.1 197.0 200.6 204.4 207.2 209.0 210.0 210.0 222.0 87 88 89 104 105 106 107 108 109 110 Fr Ra Ac Rf Db Sg Bh Hs Mt Ds (223) (226) (227) (261) (262) (266) (262) (277) (268) ( ) 58 59 60 61 62 63 64 65 66 67 68 69 70 71 Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu 140.1 141.0 144.2 145.0 150.3 152.0 157.2 158.9 162.5 164.9 167.3 168.9 173.0 175.0 90 91 92 93 94 95 96 97 98 99 100 101 102 103 Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr 232.0 231.0 238.0 (237) (244) (243) (247) (247) (251) (252) (257) (258) (259) (260) g = 9 . 81 m/s 2 d water = 1 . 00 g/mL 1 atm = 1.01325 × 10 5 Pa N A = 6 . 022 × 10 23 mol - 1 k = 1 . 381 × 10 - 23 J/K PLEASE NOTE: You will NOT have ac- cess to the Homework Service until 2 PM today (12/7/2005). At that time you will be able to access the solutions and see your scores. R = 0 . 08206 L · atm/mol · K R = 8 . 314 J/mol · K R = 62 . 36 L · torr/mol · K 1 L · atm = 101.325 J Water Data C s , ice = 2 . 09 J/g C C s , water = 4 . 184 J/g C C s , steam = 2 . 03 J/g C Δ H fusion = 334 J/g Δ H vapor = 2260 J/g
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Pham, Quoc – Exam 4 – Due: Dec 7 2005, 3:00 pm – Inst: McCord 2 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. 001 (part 1 oF 1) 10 points The molar entropy oF lead at 298 K is equal to the area under the curve obtained by plotting which oF the Following From T = 0 to 298 K? 1. ln C p versus T 2. C p versus T 3. C p versus 1 T 4. C p T versus T correct 5. ln µ C p T versus T Explanation: 002 (part 1 oF 1) 12 points Calculate the standard enthalpy change For the reaction 2 HCl(g) + ± 2 (g) 2 H±( ) + Cl 2 (g) given 4 HCl(g) + O 2 (g) 2 H 2 O( ) + 2 Cl 2 (g) Δ H 0 = - 202 . 4 kJ/mol rxn 1 2 H 2 (g) + 1 2 ± 2 (g) H±( ) Δ H 0 = - 600 . 0 kJ/mol rxn H 2 (g) + 1 2 O 2 (g) H 2 O( ) Δ H 0 = - 285
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This note was uploaded on 03/19/2008 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas at Austin.

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C301 Exam 4 solutions - 1A 1 H 1.008 3 Li 6.94 11 Na 22.99...

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