Unit 9 Exercise.docx - Running head UNIT 9 EXERCISES Unit 9 Exercises Ali Gharibi Statistics for Business Professor Albert Wong Yorkville University

Unit 9 Exercise.docx - Running head UNIT 9 EXERCISES Unit 9...

This preview shows page 1 - 4 out of 9 pages.

Running head: UNIT 9 EXERCISESUnit 9 ExercisesAli GharibiStatistics for BusinessProfessor Albert WongYorkville University
Background image
Unit 9 Exercises1.a: P=(200×0.65)+(250×0.7)200+250=0.67781.b: z=0.650.70.6778(10.67)(1200+1250)=−1.111.c: The Z critical value at α=0.05 is -1.645Reject the null hypothesis if statistic value is less than -1.6451.d: The test statistic value is -1.11 is greater than -1.645 so doesn’t reject the null hypothesis.1.e: P-value (-1.11) = 0.1331.f:(0.650.7)±1.96.0.65(10.65)200+0.7(10.7)250=(−0.1355,0.0355)2.a:122127280ˆˆ0.7579;0.6957195115XXppnn2.b: p = 0.7238z12ˆˆ0.75790.6957121.00411110.7238 10.723895115pppqnn
Background image
2.c: The p-value corresponding the test is =2*(1-NORMSDIST (1.004)) =0.3153The p-value is greater than 0.05, don’t reject null hypothesis. No. The firm couldn’t conclude that the proportion of employees within the two regions who plan to stay with the company one year from now is not the same. 2.d: 0.7579 10.75790.6957 10.69570.75790.69571.9695115= (-0.058,0.183)3.a:Null hypothesis: There is no change in proportion of members who would recommend the CreditUnion to their family and friends have increased as a result of the pilot.
Background image
Image of page 4

You've reached the end of your free preview.

Want to read all 9 pages?

  • Winter '15
  • Business

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture