5362_HW1_Sol.pdf - Solution of Homework 1 Problem 1 1 2 3...

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1 Solution of Homework 1 September 1 4 , 201 7 Problem 1)
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Problem 2: ࠵? (࠵?) = ࠵? (࠵?)|࠵?(࠵?)| = ൜ 10 ି଻ (1 − 10 ି଻ |࠵?|), 0.475 × 10 ≤ |࠵?| ≤ 0.525 × 10 0 , ࠵?࠵?ℎ࠵?࠵?࠵? ࠵? = 2 න ࠵? (࠵?)࠵?࠵? = න ࠵? (࠵?)|࠵?(࠵?)| ଴.ହଶହ×ଵ଴ ଴.ସ଻ହ×ଵ଴ ࠵?࠵? = 2 × (5.25 × 10 ି଼ + 4.75 × 10 ି଼ ) × 0.05 × 10 ÷ 2 = 0.05 -5 M 5 M 0.5 M 0.5 M 1 ) ( f s x -10M 10M ) ( f H
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Problem 3: S1 S2 S3 S4 Gray encoding 00 01 11 10 Encoding 2 00 01 10 11 Encoding 3 00 10 01 11 Main function: R1=encoding([0 0],[0 1],[1 1],[1 0]);% R1 is Gray encoding R2=encoding([0 0],[0 1],[1 0],[1 1]);% R2 is encoding 2 R3=encoding([0 0],[1 0],[0 1],[1 1]);% R3 is encoding 3 semilogy(1:20,R1, '+-' ,1:20,R2, '-' ,1:20,R3, '*-' ) legend( 'Gray encoding' , 'encoding scheme 2' , 'encoding scheme3' ) Encdoding function: function R=encoding(symbol1,symbol2,symbol3,symbol4) symbol=randint(1,1e6);
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