ch304 hw5 - dh2964 Homework 5 Walker (53970) This print-out...

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dh2964 – Homework 5 – Walker – (53970) 1 This print-out should have 28 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 1.0 points In carbon-containing compounds, carbon usually Forms 1. Four bonds, nitrogen usually Forms fve bonds, oxygen usually Forms six bonds, and hydrogen only Forms one bond. 2. Four bonds, nitrogen and oxygen usually Form two bonds, and hydrogen only Forms one bond. 3. three bonds, nitrogen and oxygen usually Form two bonds, and hydrogen only Forms one bond. 4. Four bonds, nitrogen usually Forms three bonds, oxygen usually Forms two bonds, and hydrogen only Forms one bond. correct Explanation: These bonding schemes C N O H b allow each atom (except H) to have a complete octet oF valence electrons. 002 1.0 points Which oF the Following is the correct Lewis Formula For boron trichloride (BCl 3 )? 1. Cl B Cl b b b b Cl 2. b b b b b b b b b b b b b b b b b b b b Cl B Cl Cl 3. Cl B Cl Cl b b b b b b b b b b 4. Cl B Cl Cl 5. Cl b b b b b b B Cl b b b b Cl b b b b b b 6. b b b b b b b b b b b b Cl B Cl Cl 7. b b b b b b Cl B Cl Cl 8. b b b b b b b b Cl B Cl Cl 9. b b b b b b b b b b b b b b b b b b Cl B Cl Cl correct 10. b b b b b b b b b b b b b b Cl B Cl Cl Explanation: B contributes 3 valence e and each Cl contributes 7 valence e For a total oF 24 e . B is a known exception to the octet rule and can Form stable with 6 valence e : b b b b b b b b b b b b b b b b b b Cl B Cl Cl 003 1.0 points Draw the Lewis dot structure For S± 4 . How
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dh2964 – Homework 5 – Walker – (53970) 2 many lone pairs of electrons are on the central atom? 1. 1 correct 2. 3 3. 2 4. 0 5. 4 Explanation: S has 6 valence e F has 4 ( 7 valence e ) Total = 34 e S F b F F F b b has 34 e and S is a known exception to the octet rule so the structure is correct as drawn. There is 1 lone pair on S, the central atom. 004 1.0 points Which one of the following compounds does NOT obey the octet rule? 1. H 2 O 2. SF 6 correct 3. CH 4 4. NH 3 Explanation: S has 6 valence e F has 6 × 7 valence e Total = 48 valence e S F b b b b b b F F F F F SF 6 has 48 e but S has an expanded valence shell containing 12 e , thus violating the octet rule. 005 1.0 points The valence shell electron pair repulsion the- ory (VSEPR) is used to 1. predict the electronegativity of atoms. 2. predict the bonding pattern in molecules. 3. predict the number of multiple bonds in a molecule. 4.
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ch304 hw5 - dh2964 Homework 5 Walker (53970) This print-out...

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