lab5.pdf

# lab5.pdf - Exercise 1 Getting to know iperf3(a iperf3 s(b...

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Exercise 1 - Getting to know iperf3 (a) iperf3 –s (b) start iperf as the client and the server ip address is 192.168.1.17. The messages are send by UDP and to server’s port number is 8911. (c) TCP will be used instead of UDP. Exercise 2 - When does IP fragmentation occur? 1472 is the maximum size of the UDP datagram can be sent without IP fragmentation. The MTU of eth0 is 1500. And the IP header is 20 bytes. According to the observation, everytime there are 8 bytes data are added to the payload. Therefore, fragmentation will occur if the total size of data before sending is more than 1472 byte (1500 – 20 – 8 = 1472). Exercise 3 - Examining the IP Fragments 13:55:55.879857 IP (tos 0x0, ttl 64, id 54532, offset 0, flags [DF], proto UDP (17), length 32) 128.238.66.107.46154 > 128.238.66.106.5201: UDP, length 4 13:55:55.918912 IP (tos 0x0, ttl 64, id 54536, offset 0, flags [+], proto UDP (17), length 1500) 128.238.66.107.46154 > 128.238.66.106.5201: UDP, length 10000

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13:55:55.918916 IP (tos 0x0, ttl 64, id 54536, offset 1480, flags [+], proto UDP (17), length 1500) 128.238.66.107 > 128.238.66.106: ip-proto-17 13:55:55.918916 IP (tos 0x0, ttl 64, id 54536, offset 2960, flags [+], proto UDP (17), length 1500) 128.238.66.107 > 128.238.66.106: ip-proto-17 13:55:55.918917 IP (tos 0x0, ttl 64, id 54536, offset 4440, flags [+], proto UDP (17), length 1500) 128.238.66.107 > 128.238.66.106: ip-proto-17 13:55:55.918917 IP (tos 0x0, ttl 64, id 54536, offset 5920, flags [+], proto UDP (17), length 1500) 128.238.66.107 > 128.238.66.106: ip-proto-17 13:55:55.918918 IP (tos 0x0, ttl 64, id 54536, offset 7400, flags [+], proto UDP (17), length 1500)
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