combinepdf-min-0424.pdf - Example 10 Find the Cartesian...

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Unformatted text preview: Example 10. Find the Cartesian form of the plane x = 1 + A 1 + ,u 0 for A, p: E R. 2 1 2 371 SOLUTION. Let x = 3:2 . By comparing the components, we get the following parametric 333 equations $1=1+A—n, $2=1+A and $3=2+A+2n. Hence from the second equation, we get A = 3:2 — 1. Substitute this into the first equation, we have $1 = 1 —|— (3:2 — 1) — ,u and that is ,u; = 332 — 391. Now substitute A and n which are in terms of 3:1 and 2:2 into the third parametric equation. The Cartesian form of the plane is, therefore, m3=2+(m2—1)+2($2—m1) or 2391—3m3+$3=1. 1.6 Vectors, Matrices / Arrays and MATLAB Tn +1‘1‘:C’1 nnn‘l‘lnn 11TH Trr'l-l-l nlnnfr'r larwr'r +f‘l I‘WT‘IT‘lfq-ln Trnn‘l‘n‘wc n‘nrq mn‘l‘v‘lnnn fnvvn‘trfl '1“ “1'1— fir-PT hp Vfi1'l fl-l'lfi'l1llq ...
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