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CHENNAI MATHEMATICAL INSTITUTE CLASSICAL MECHANICS I PROBLEM SHEET X 29th October 2012 date due 5th Nov 2012 Barn and Pole paradox: There is barn (BAEFD) of length L (AB = L) in it’s rest frame. D is a door which is open initially and can be closed. A person P carrying a pole of rest length L is coming with a velocity V with respect to the barn. Consider the set of events from the barn’s frame . The length of the pole would be L where γ = (1 - V 2 / c 2 ) - 1 / 2 and so concludes that the moment the front end of the pole Y, touches the back of the wall AE he can close the door D as the length of the pole is less than L. ( The door D is initially kept open ). The person P carrying the pole would conclude the length AB of the barn is only L and so when the front end Y touches the backend X would be outside and so the door cannot be closed. The resolution of the paradox occurs when you solve the next two problems 46. How do the set of events appear from the two frames: (a) Y touches the wall AE. (b) the door closed at the time the pole touches AE as seen
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