problemas 3 y 4.docx

# problemas 3 y 4.docx - Ejercicio 3 Hallar 1 1 2 x 3 x 2 2=0...

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Ejercicio 3. Hallar x . x 1 / 2 3 x 1 2 + 2 = 0 x 3 x + 2 = 0 x + 2 = 3 x x ( x + 2 ) = 3 x + 2 x = 3 x + 2 x 3 = 0 x + 2 x 1 / 2 3 = 0 ( x 1 / 2 + 3 )( x 1 / 2 1 ) = 0 x 1 / 2 + 3 = 0 x 1 / 2 =− 3 ( x ) 2 = ( 3 ) 2 x = 9 x 1 / 2 1 = 0 x 1 / 2 = 1 ( x ) 2 = ( 1 ) 2

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x = 1 NOTA: Solo se utiliza x = 1 por que es el que si da. Ejercicio 4 4 x 2 x 8 4 x 2 + 3 x + 4 + 2 = 0 4 x 2 x 8 = 4 x 2 + 3 x + 4 2 ( 4 x 2 x 8 ) 2 = ( 4 x 2 + 3 x + 4 2 ) 2 4 x 2 x 8 = ( 4 x 2 + 3 x + 4 2 ) 2 ( 2 ) ( 2 ) ( 4 x 2 + 3 x + 4 ) + 4 4 x 2 x 8 = 4 x 2 + 3 x + 4 4 4 x 2 + 3 x + 4 + 4 4 x 16 =− 4 4 x 2 + 3 x + 4
( 4 x 16 ) 2 = ( 4 4 x 2 + 3 x + 4 ) 2 ( 4 x ) 2 ( 2 ) ( 4 x ) ( 16 ) + ( 16 ) 2 = 16 ( 4 x 2 + 3 x + 4 ) 16 x 2 + 128 x + 256 = 62 x 2 + 48 x + 64 48 x 2 + 80 x + 192 = 0 16 ( 3 x 2 + 5 x + 12 ) = 0 3 x 2 + 5 x + 12 = 0 16 5 ±

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