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Unformatted text preview: PHYS 211 Discussion 1-D & 2-D Kinematics Session 1 Solution Bonnie and Clyde (from Minnesota Cooperative Group Problems #12) In your new job, you are the technical advisor for the writers of a gangster movie about Bonnie and Clyde. In one scene Bonnie and Clyde try to flee from one state to another. If they get across the state line, they could evade capture, at least for a while until they become Federal fugitives. In the script, Bonnie is driving down the highway at 108 km/hr and passes a concealed police car that is 1 km from the state line. The instant Bonnie and Clyde pass the patrol car, the cop pulls onto the highway and accelerates at a constant rate of 2 m/sz. The writers want to know if they make it across the state line before the pursuing cop catches up with them. TWS Is Oz 10 Kinematics Pmblcm. TMW are, (3me {No.66 +0 Wok ‘I‘C JVVW‘S 30% M08: 6) iii/10¢ We ijime col/Lem Bonwiegzdtfi$e F088 We, 5% limb and (154130 #6) anl coma We copis. @ (Find HA6 time udlfle/Wfiwmkch C/Lbcifi (Easswl'I/v; state, Uflb email WPWe CE’ \lo wmmeo§>&o~€§ ng. EC W6 Cap orbsscs earl/(of) El meamolrxe (meal/w mam. @ Rd wmwe, up games mm ml C 9: +0 We» SJWCR» Uma Ale’rcwxca. - W Wall Show am @ Mg) F?” QM géwfldfl) (600 mosi’ Q‘LFSJV comUer’b odt distances gauge ATM/x55 80 W ORA/PIE) maj’dx/Lv U80 : \08 L‘W/W ’3 <30 ”/5 Ax= ll<m=kooom @ Racking) *Hme-l—b mg We \ooficger; mg 2L 1 ; Xzfl—l—Uo‘b—t— 2:685 . X:3<§+>L5/jo+:0tJC fl. l 9» x 2 $53.: X _ 510*» rm "H | ‘,,_.._.._,— PHYS 211 Discussion 1-D & 2-D Kinematics Session .1 Solution w: m COP grams M) 4% Wm, Wm? Roe/W W Gui/m WQ/we/ JO. gaw'ws WM egymfim 4;” X 3 Xibc : X0 PHYS 211 Discussion 1—D & 2-D Kinematics Session 1 Solution Catching the Train You are going to Chicago for the weekend and you decide to go first—class by taking the AmTrak train. Unfortunately, you are late finishing your mathematics exam, so you arrive late at the train station. You run as fast as you can, but just as you reach the platform your train departs, 30 meters ahead of you down the platform. You can run at a maximum speed of 8 m/s and the train is accelerating at 0.8 m/s2. You can run along the platform for 50 meters before a barrier prevents you from going further. Will you catch your train? [\l o \{\€/€&t “l‘O CJYWMJV UWt’iE “HA6 “Hm/R) WWBH/h/rfs is W\ vwefl’QfB. wk: pic/fife m>$\/\+ (MAE V6649 Jamel/— CC dine, ingcfm‘l’lmé \f6 : Xm/s 0‘: O Fem/6'2. Om 36m 50m For new, letéi ignore, Whernef afi dug‘l’ Cvxcgt 00+ 03W SW wild ca+olrx MP6 ffowfl 7(: your poSN‘Hmfl X3260 +QOJQO+§§EQ ><:\ij0 x:(\ 03 Tmm Fasten X: >< twig-Lt 30801 )KZXO‘JEQJCQN 3%..) r\ WA 600 @CVCJA Jrineirm‘m) x WA 36 com be. 63(an in \DO’HA efiruodfloflfi. Uv‘blfli’) ‘Wfifi ingofmodfiofl) SONQ %r K. TWS Ii: Smaller W 50m (We Kococi’lm 09% WWW/(3 So &m~ cram ”\cmr Jvmln PHYS 211 Discussion l-D & 2-D Kinematics Session 1 Solution Falling Brick As you are cycling to classes one day, you pass a construction site on Green Street for a new building and stop to watch for a few minutes. A crane is lifting a batch of bricks on a pallet to an upper floor of the building. Suddenly, a brick falls off while the pallet is rising. You clock the time it takes the brick to hit the ground at 2.4 seconds. The crane, fortunately, has height markings, and you see the brick fall off the pallet at a height of 13 meters above the ground. A falling brick, as we all know, can be dangerous, and you wonder how fast the brick was going when it hit the ground. Since you are taking physics, you quickly calculate the answer. ' Leas W m Mined) We The, ‘0’in is m ‘HAQJ fifiifls WW9 WWMg UO>O. ] “Se, m hN‘LWACQ ‘. <1er inPorerim ’50 9me v0 2 a Jc E33310 ”036 ”will” 0 :- 12) + v, Limb + 5649)er You skew; QM v, = C034- "4% UsMS M5 mo in?0!‘m0CP\dY\) 3ft) Can Rfi \Lg '. p 7,: 7’ [No’i‘ei A3 \‘5 Mfiikwa’ \lpavo’t 090 or \IP v V, 'hlaAS Yaw shru‘A 3mg PHYS 211 Discussion 1-D & 2-D Kinematics Session 1 Solution Escape from Burning Building Your friend, a world- class long jumper, is trapped on the roof of a burning building. His only escape route is to jump to the roof of the next building. Fortunately for him, he is in telephone contact with you, a Physics 211 student, for advice on how to proceed. He has two options. He can jump to the next building by using the long-jump technique where he jumps at 450 to the horizontal. Or, he can take his chances by staying where he 13 in the hopes that the fire department will rescue him You learn from the building engineers that the next building 13 10 m away horizontally and the roof 1s 3 m below the roof of the burning building. You also know that his best long- jump distance 15 7. 9 m. What do you advise him to do? TVQ$ ‘16 a Eli) thaficé ”(0(5le 60 we/ (\an have; +0 ‘HA‘ML/l chow \JQC/‘EOF WVMW‘BE' You Know WMSPM Exam QflQ/nci) Wefl$ ~i’oQUWk ) Wbm Qiofl'b knew [Mg 1m a9 Sp€€&\. We, Can age We \CMEB 3““? iniiwmafim’to cictflrmlme V0" ' 1 — - : 1*! ‘6; W3 duh/we > / / \ \ \ l3) <30 won an 2;;\ X 2 X0 +U0x£+§aha 5(CO KE7qm :y—0 3 ‘0 PHYS 211 Discussion 1-D & 2-D Kinematics Session 1 Solution (More “0+ m 341% \, T) 6626 ”to 30W ‘C‘flm §MEJUM¥) We, WQQCO Jet) Qmoj‘ 00+ \/\O\/\S gaf \ALESOQS wH’I/x‘H/KLUOWQ POM oWflmeW%mW§[email protected]®P : O we JV Lag JC 33 s o #5 = Owé 3%m©~b+§(—fi.%\£l >< 10+ Vocofig‘b »_. _______'____,._7 wmmnow}xcwsqu PC 13 $0vC€ QOF do)? QflQ/w/‘(g ”bQQmP. PHYS 211 Discussion 1-D & 2-D Kinematics Session 1 Solution Skydivers The U of I Skydiving Club has asked you to plan a stunt for an air show. In this stunt, two skydivers will step out of opposite sides of a stationary hot air balloon 5,000 feet above the ground. The second skydiver will leave the balloon 20 seconds after the first skydiver, but you want them both to land on the ground at the same time. The show is planned for a day with no wind so you may assume all motion is vertical. To get a rough idea of the situation, assume that a skydiver will fall with a constant acceleration of 32 ft/sec2 before the parachute opens. As soon as the parachute is opened, the skydiver falls with a constant speed of 10 ft/sec. If the first skydiver, Sue, waits 3 seconds after stepping out of the balloon before opening her parachute, how long must the second skydiver, Joe, wait after leaving the balloon before opening his parachute? Crab Sub $0.03 fills: v = log/s m Cst [figs 3w woidfi waits imam loft/g taco tl:3$ EQZQOS gt? th—Z? WK Mb looking 9% t 3 b3 ’ fig 31m, PUllSl/tlg POM—0W so W Wad/ml 8% will del 0ij MM Sowvxe/ 36mm» Fawn J05 ’l‘o JULk loo’ih skisédxieflg gall 03v ~H/\2/ SCH/we 396%) So ‘Bhels moS‘i’ SKAMLWQ/ Sam/\e/ «0051*th Pramq 153 +1) t4 Cor QXSe/ W93 0mm: wfiyawtfl ' ' 7%ng \émvo 35...». C t3} : moi—h; W {s can? Wat v a tacit: wwfi‘aat bobbxi 3 Sec ”WWI; JCHVDJCa; lDWC/‘AU‘LC W9“ “7+9 ‘- its? jx+GZl7+t> 59.: HOW 0400er 853%Ct3)? 360 +0 J02 3 Iflo‘fi/fiw \flfilpPQA/fi SOGDL-g‘ U? Q em e3 : {imam be Jc swat: 33313045 JD 4« ..i - j w" 3262333 it M 5333:: '21 V“ " 7 (a “2):“ <\ v ...
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