TD #2 - ELE1403H09 Travauxdirigs Sance2 Corrig Exercice 1...

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ELE 1403 H 0 9 Travaux dirigés Séance 2 Corrigé () ) () ( ( ) ) 11 1 22 33 2 f=60 Hz , 3 120 0 V 80 60,3 100,2 37 1 260 149,9 300,1 30 150 113,3 188 37 a) Prise de courant usuelle ZRj L j C j L j ω = =∠ =+ = =− = = = + = D D D D ± ± Exercice 1 V 1 1 1 77 rad s 120 0 1, 2 37 A 100,2 37 2 Z it == D D D ± V I cos 377 37 1,7cos 377 37 A tt −= DD
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() 2 3 2 3 3 3 123 2 120 0 0,4 30 A 300,1 30 0,4 2 cos 377 30 0,57cos 377 30 A 120 0 0,64 37 A 188 37 2 cos 377 37 0,91cos 377 37 A 1,2 37 0,4 30 37 2,03 26,5 Z it t t Z t t b) == =∠ ∠− + = + = −= ++ + + = D D D DD D D D D D ± ± ± ± ±±± ± ± V I V I I=I I I I= A 2 cos 377 26,5 2,87cos 377 26,5 A 120 0 59,1 26,5 t t c) Z = = = D D D D ± V ( ) 5 VA D 11 1 26,5 59,2 111 1 1 1 100,2 37 300,1 30 188 37 120 0 1,2 37 144 37 VA 115 86,7 VA 115 W , Z ZZZ d) S Sj PQ + + ∠∠ × = =+ D D ± ±± I VI () ( ) ( ) 22 2 33 3 1 2 3 var 120 0 30 48 30 VA 41,6 24 VA 41,6 W , 24 var 120 0 0,64 37 76,8 37 VA 61,3 46,2 VA 61,3 W , var 217,9 108,9 243,6 26, cos 26 S S S S SP P P j Q Q Q j Fp × = =− ×∠ = = + = = DDD D VI VI ,5 0,89 D
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() 123 11 2 2 217,9 W 108,9 var 217,9 W tan cos 217,9 tan cos 0,95 71,6 var 71.6 108,9 37,3 var 120 386,1 S S S SS S C C C e) Avant compensation PP QQ Q Q Après compensation QP F p Q X Q −− =++= = × + = =− = == = ± V 3 C C X ω ×− 6,87 F 86,1 377 μ = × 6 16 1 6 1 6 22 6 6 2 2 2 66 6 12 66 1) 30 MW 30 10 W tan cos 30 10 tan cos 0,6 40 10 var 45 Mvar 45 10 var 45 10 60 10 W t a nc o s t a o s0 , 8 30 10 60 10 90 10 W 40 10 45 10 85 ch ch f p Q P fp
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This note was uploaded on 04/21/2009 for the course ELE ELE1403 taught by Professor Khaled during the Spring '09 term at NYU Poly.

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TD #2 - ELE1403H09 Travauxdirigs Sance2 Corrig Exercice 1...

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